Question

Breeder reactors are used to convert the nonfissionable nuclide${}_{\mathbf{92}}{}^{\mathbf{238}}\mathbf{U}$ to a fissionable product. Neutron capture of the${}_{\mathbf{92}}{}^{\mathbf{238}}\mathbf{U}$ is followed by two successive beta decays. What is the final fissionable product?

Short answer

The final fissionable product is ${}_{94}{}^{239}\mathrm{Pu}$.

Step-by-step solution

Fissionable product.

The fissionable product can be defined as the radionuclide which has the capability to undergo a fission reaction after absorbing the thermal neutron or fast neutron.

The final fissionable product.

The particles like alpha, beta, and gamma rays are emitted by the unstable radioactive nucleus to gain a stable configuration.

The following chemical equation is representing the nuclear reaction of beta decay of uranium-238.

• Neutron capture ${}_{92}{}^{238}{\mathrm{U}+}_0^1\mathrm{n}{\to }_{92}^{239}\mathrm{U}$:

• The first step reaction ${}_{92}{}^{239}\mathrm{U}{\to }_{-1}^0{\mathrm{e}+}_{93}^{239}\mathrm{Np}$:

• The second step reaction ${}_{93}{}^{239}\mathrm{Np}{\to }_{-1}^0{\mathrm{e}+}_{94}^{239}\mathrm{Pu}$:

Now, the final fissionable product is ${}_{94}{}^{239}\mathrm{Pu}$.