Question

An unknown binary compound containing hydrogen (XH_n) has density as a gas that is 2.393 times that of oxygen gas under the same conditions. When $\mathbf{2}\mathbf{.}\mathbf{23}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{2}}$mole of this compound reacts with excess oxygen gas, 0.803g of water is produced. Identify the element X in this compound.

Short answer

The element of X is 72.55g/mol is germanium

Step-by-step solution

Molar mass of XHn

Given that molar mass of density is 2.393 times of oxygen gas.

Molar mass of XH_n = $2.393\times Molarmasof{O}_2$

= 2.393

Molar mass of XH_n = 76.58gmol

Molar mass of the compound

Molar mass of X = Molar mass of XH_n - 4(Molar mass of H)

= 76.58g/mol - 4(1.008g/mol)

Molar mass of X = 72.55g/mol

Conclusion

Therefore, the element of the compound is = 72.55g/mol is germanium (Ge)