Question

Consider the equation $\mathit{A}\mathbf{+}\mathbf{2}\mathit{B}\mathbf{\to }\mathit{A}{\mathit{B}}_{\mathbf{2}}$ Imagine that 10 moles of A is reacted with 26 moles of B.Use a scale from 0 to 10 to express your level of agreement with each of the following statements. Justify and discuss your responses.
a. There will be some As left over.
b. There will be some Bs left over.
c. Because of leftover As, some ${\mathit{A}}_{\mathbf{2}}$molecules will be formed.
d. Because of leftover Bs, some ${\mathit{B}}_{\mathbf{2}}$molecules will be formed.
e. Even if A is not limiting, ${\mathit{A}}_{\mathbf{2}}$ molecules will be formed.
f. Even if B is not limiting, role="math" localid="1662120548192" ${\mathit{B}}_{\mathbf{2}}$ molecules will be formed.
g. Along with the molecule AB₂, molecules with the formula ${\mathit{A}}_{\mathbf{x}}\mathbf{}{\mathit{B}}_{\mathbf{Y}}$(other than$\mathit{A}{\mathit{B}}_{\mathbf{2}}$ ) will be formed.

Short answer

Statements a, c, d, e, f are agreed to the level of 0; statement g is agreed to the level of 1, and statement b to 10.

Step-by-step solution

Equation and its ratio

The initial step is to write down the equation.

$\mathbf{A}\mathbf{+}\mathbf{2}\mathbf{B}\to {\mathbf{AB}}_{\mathbf{2}}$

There is a combination of 10 moles of A and 26 moles of B. But, according to the balanced chemical equation, 10 moles of A requires only 20 moles of B. But, it is given 26 moles of B. So the excess 6 moles of B remains unreacted.

There will be some “As” left over

As the amount A is consumed completely, the given option (a) is wrong. It has 0 agreement level.

There will be some “Bs” left over

There are 20 moles of B consumed in the reaction and still, there are 6 moles left. The statement will be agreed to the level of 10.

Because of leftover “As”, some A2 molecules will be formed

There are no As left here. So, there is no A₂molecule formation. The statement will be agreed to the level of 0.

Because of leftover “Bs”, some B2 molecules will be formed

There is no Bs left here. There is a balance of Bs in the mixture. “A” completely reacts with “B”. The statement will be agreed to the level of 0.

Even if A is not limiting, A2  , molecules will be formed

The limiting reactant is A and there are no As left. There is no chance for A₂ molecule formation. The statement will be agreed to the level of 0.

Even if B is not limiting, B2 molecules will be formed.

B is not a limiting reagent. There is no remaining B in the mixture. “A” completely reacts with “B”. The statement will be agreed to the level of 0.

Along with the molecule AB2, molecules with the formula AxBy  (other thanAB2 ) will be formed.

This can be correct depending upon the formation of A and B ions. The statement will be agreed to the level of 1.