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Table 10.2 shows the possible arrangements of four molecules in a two-bulbed flask. What are the possible arrangements if there is one molecule in this two-bulbed flask or two molecules or three molecules? For each, what arrangement is most likely?

Short Answer

Expert verified

A spontaneous process is a process that can occur on its own.

Lack of order or randomness in a system or in surroundings is called entropy.

Positional probability is the number of configurations in space that yield a particular state.

A system is defined as a region in space means region which undergo change. Everything other than system is known as surrounding.

System + Surrounding = Universe.

Step by step solution

01

Only One Molecule is Present

If only one molecule is present then only one arrangement possible with two microstates.

Both have equal probability to happen.

02

Only Two Molecules are Present

If only two molecules are present then only three arrangements are possible and the most likely is when each bulb has one molecule(centre one).

03

Only Three Molecules are Present

If only three molecules are present then only four arrangements are possible and the most likely is when one bulb has two molecules and other has one molecule.

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Most popular questions from this chapter

Consider 1.00 mole of an ideal gas at 25ยฐC.
a. Calculate q,w,โˆ†E,โˆ†S,โˆ†Handโˆ†G for the expansion of this gas isothermally and irreversibly from 2.45ร—10-2 atm to 2.45ร—10-3 atm in one step.
b. Calculate for the same change of pressure as in part a but performed isothermally and reversibly.
c. Calculate localid="1649303003894" q,w,โˆ†E,โˆ†S,โˆ†Handโˆ†Gfor the one-step so thermal, irreversible compression of 1.00 mole of an ideal gas at 25ยฐC from 2.45ร—10-3atm to 2.45ร—10-3atm.
d. Construct the PV diagrams for the processes described in parts a, b, and c.
e. Calculate the entropy change in the surroundings for the processes described in parts a, b, and c.

Consider the reaction

2NO2(g)โ‡”N2O4(g)

For each of the mixtures of reactants andproducts at 25ยฐC, predict the direction in which the reaction will shift to reach equilibrium. Use thermodynamic data in Appendix 4.

  1. PNO2=PN2O4=1.0atm
  2. PNO2=0.21atm,PN2O4=0.50atm
  3. PNO2=0.29atm,PN2O4=1.6atm

129. Given the thermodynamic data below, calculate โˆ†S andโˆ†Ssurr for the following reaction at 25ยฐC and 1 atm:
XeF6(g)โ†’XeF4(s)+F2(g)

โˆ†Hfo(kJ/mol)

So(JK-1mol-1)

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300

XeF4(s)

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146

F2(g)

0

203

A friend tells you โ€œFree energy G and pressure P are directly related by the equation

G=Gยฐ+RTln(P)

Also, G is related to the equilibrium constant K in that when Gproducts = Greactants, the system is at equilibrium. Therefore, it must be true that a system is at equilibrium when all pressures are equal.โ€ Do you agree with this friend? Explain.

Consider the reaction

2POCl3(g)โ†’2PCl3(g)+O2(g)

  1. Calculate ฮ”Gofor this reaction. The ฮ”GR0values for 2POCl3(g)and 2PCl3(g)are \(-502kJ/mol\)and \(-270kJ/mol\), respectively.
  2. Is this reaction spontaneous under standard conditions at 298K?
  3. The value of ฮ”Sofor this reaction is 179J/K . At what temperatures is this reaction spontaneous at standard conditions? Assume that ฮ”Ho and ฮ”Sodo not depend on temperature.
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