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Monochloroethane (C2H5Cl) can be produced by thedirect reaction of ethane gas (C2H6) with chlorine gas orby the reaction of ethylene gas (C2H4) with hydrogenchloride gas. The second reaction gives almost a 100%yield of pure C2H5Clat a rapid rate without catalysis.The first method requires light as an energy source orthe reaction would not occur. YetΔGo for the first reaction is considerably more negative thanΔGo for thesecond reaction. Explain how this can be so.

Short Answer

Expert verified

For kinetic reasons, the first reaction requires a light source. The first reaction takes a long timeif a light source is present. The thermodynamics of a reaction does not affect its kinetics. Even if the first reaction has a better thermodynamic advantage, it has a worse kinetic advantage. The second reaction is fast and unpleasant. When determining whether or not a reaction will occur, both kinetics and thermodynamics must be taken into account.

Step by step solution

01

Step 1: Explanation for chloromethane manufacture

Themanufacture of chloromethane is described using two ways. The first approach involvesproducing chloroethane by reacting ethane gas directly withchlorine gas, whereasthe second method requires reacting ethylene gas with hydrogen chloride gas. The second reaction yield is estimated to be almost 100%.

02

Explanation for first and second reaction

Thefirst reaction necessitates theuse of a light source for kinetic reasons. If a light source is present, the first reaction takes a long time to occur. The kinetics of a reaction is unaffected by the reaction's thermodynamics. Even if the first reaction is more advantageous in terms of thermodynamics, it is unfavorable in terms of kinetics. Thesecond reaction israpid and has a negativevalue. Bothkinetics and thermodynamics must be considered when determining whether or not a reaction will occur.

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Most popular questions from this chapter

Sodium chloride is added to water (at 25°C) until it issaturated. Calculate the Cl-concentration in such a solution.

Impure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into metal from 99.90% to 99.99% purity by the Mond process. The primary reaction involved in the Mond process is
Ni(s)+4CO(g)Ni(CO)4(g)
a. Without referring to Appendix 4, predict the sign ofS° for the preceding reaction. Explain.
b. The spontaneity of the preceding reaction is temperature-dependent. Predict the sign of SSUIT for this reaction. Explain.
c. For, Ni(CO)4(g),Ht°=-607kj/moland S°=417J-1mol-1 at 298 K. Using these values and data in Appendix 4, calculate H°andS° for the preceding reaction.
d. Calculate the temperature at which G°=0(K=1) for the preceding reaction, assuming that H°andS° do not depend on temperature.
e. The first step of the Mond process involves equilibrating impure nickel with COgandNiCO4gatabout 50°C. The purpose of this step is to convert as much nickel as possible into the gas phase. Calculate the equilibrium constant for the preceding reaction at 50.°C.
f. In the second step of the Mond process, the gaseousNiCO4g is isolated and heated at 227°C. The purpose of this step is to deposit as much nickel as possible as pure solid (the reverse of the preceding reaction). Calculate the equilibrium constant for the preceding reaction at 227°C.
g. Why is temperature increased for the second step of the Mond process?

h. The Mond process relies on the volatility of NiCO4 for its success. Only pressures and temperatures at which NiCO4, is a gas are useful. A recently developed variation of the Mond process carries out the first step at higher pressures and a temperature of 152°C. Estimate the maximum pressure of NiCO4gthat can be attained before the gas will liquefy at 152°C. The boiling point for NiCO4is 42°C, and the enthalpy of vaporization is29.0kJ/mol . (Hint: The phase-change reaction and the corresponding equilibrium expression are
NiCO4INiCO4gK=PNiCO4
NiCO4gwill liquefy when the pressure of role="math" NiCO4is greater than the K value.)

It is quite common for a solid to change from one structure to another at a temperature below its melting point. For example, sulphur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form at temperatures above 95°C

  1. Predict the signs of HandSfor the processSrhombicSmonoclinic
  2. Which form of sulphur has the more ordered crystalline structure (has the smaller positional probability)?

The standard free energies of formation and the standard enthalpies of formation at 298 K for difluoroacetylene (C) and hexafluorobenzene (C6F6
) areFor the following reaction:

C6F6(g)3C2F2(g)

a. calculateΔSoat 298 K.
b. calculate K at 298 K.
c. estimate K at 3000. K, assuming ΔHoand ΔSodo not depend on temperature.

High temperatures are favourable to a reaction kinetically but may be unfavourable to a reaction thermodynamically. Explain.

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