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Three different organic compounds have the formula C3H8O. Only two of these isomers react with KMnO4 (a strong oxidizing agent). What are the names of the products when these isomers react with excess KMnO4?

Short Answer

Expert verified

Two isomers that can react withKMnO4are "2-propanol" and "1-propanol”, due to which 2-propanone and propanoic acid are formed as by-products.

Step by step solution

01

Formation of 2-propanone from from 2-propanol

2-Propanol undergoes oxidation in the presence of potassium permanganate (KMNO4 ) to form 2-propanone as by product. Usually primary alcohol undergoes oxidation to form carboxylic acid ,whereas 2-proponol reacts with carboxylic acid to form ketone ie 2-propanone.

02

STEP-2:  Formation of propanoic acid from propanol:

KMnO4 oxidizes 2-hydroxy propane which is a primary alcohol to carboxylic acid that is propanoic acid.

Hence the two isomers namely propanol and 2-propanol forms 2-propanone and proponoic acid.

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Most popular questions from this chapter

ABS plastic is a tough, hard plastic used in applications requiring shock resistance. The polymer consists of three monomer units: acrylonitrile(C3H3N),butadiene(C4H6),and styrene(C8H8).

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