Question

Consider the following data for xenon:

Triple point: -121⁰C, 280 torr

Normal melting point: -112⁰C

Normal boiling point: -107⁰C

Which is more dense, Xe(s) or Xe(l)? How do the melting point and boiling point of xenon depend on pressure?

Short answer

Xe(s) is more dense than Xe(l). Both the melting and boiling point of xenon increases with increase in pressure.

Step-by-step solution

Phase Diagram of Xenon

Explanation

From the above-mentioned phase diagram of Xe, it can be stated that the slope regarding the solid-liquid boundary line is positive. As a result, Xe in solid phase is denser than Xe in liquid phase. This positive slope indicates that with the increase in pressure melting point of Xe increases. It has been noted that for boiling point also there is an increase in pressure with the increase in temperature.