Question

Calculate the maximum amount of work that can beobtained from the galvanic cells at standard conditionsin Exercise 22.

Short answer

Themaximum amount of work obtained from galvanic cells at standard conditions is$\Delta G^o=-387.87 kJ \& \Delta G^o=-270.15 kJ.$

Step-by-step solution

Galvanic cell and its separation

The electrochemical cell which converts electrical energy from chemical reactions takes place in a cell called a galvanic cell. There is a separation of oxidation and reduction of half cells through salt bridge and ion movement to make it neutral.

Transfer of electron number in cell reaction of n=3

It can be denoted as:

$$\begin{gathered} E^o=1.34 V \\ \Delta G^0=-nF{E}^0 \\ \Delta G^0=-3\times 96485\times 1.34 \\ \Delta G^0=-387869.7 J \\ \Delta G^0=-387.87 kJ \end{gathered}$$

Transfer of electron number in cell reaction of n=2

It can be denoted as:

$$\begin{gathered} E^o=1.4 V \\ \Delta G^0=-nF{E}^0 \\ \Delta G^0=-2\times 96485\times 1.34 \\ \Delta G^0=-270158 J \\ \Delta G^0=-270.15 kJ \end{gathered}$$

Themaximum amount of work obtained from galvanic cells at standard conditions is role="math" localid="1663748382180" $\Delta G^o=-387.87 kJ \& \Delta G^o=-270.15 kJ.$