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In 1973 the wreckage of the Civil War ironclad USS.The monitorwas discovered near Cape Hatteras, NorthCarolina. [The Monitorand the CSS Virginia(formerlythe USS Merrimack) fought the first battle between iron armoredships.] In 1987 investigations were begun to seewhether the ship could be salvaged. Timereported (June22, 1987) that scientists were considering adding sacrificialanodes of zinc to the rapidly corroding metal hull ofthe Monitor.Describe how attaching zinc to the hullwould protect the Monitorfrom further corrosion.

Short Answer

Expert verified

The monitor’s hull can be protected by zinc because it is primarily oxidized and prevents the iron of the hull. This is because zinc is easier to oxidize as compared to iron from the above E° oxidation values.

Step by step solution

01

Analyzing the given data

In 1973, a ship was discovered near cape Hatteras, North Carolina. Efforts were made to reinstate the ship. The scientists reportedly tried addingsacrificial anodes of zincto rapidly corroding metal hull of the Monitor considering it will prevent the ship from corrosion.

02

Describing how attaching zinc to the hull would protect the monitor from further corrosion

The equations and E° oxidation are:

Fe(s)Fe2++2e-(E°=0.44V)Zn(s)Zn2++2e-(E°=0.76V)

The monitor’s hull can be protected by zinc because it is primarily oxidized and

prevents the iron of the hull. This is because zinc is easier to oxidize as compared to iron from the above E° oxidation values.

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Most popular questions from this chapter

Consider a galvanic cell at standard conditions based on
the following half-reactions:

Au3++3e-AuEo=1.5VFe3++e-Fe2+Eo=0.77V
When enough NaCl(s) is added to the compartment containing gold to make the [CI-] = 0.10 M, the cell potential is observed to be 0.31 V. Assume that Au3+ is reduced, and assume that the reaction in the compartment containing gold
Au3+(aq)+4Cl-(aq)AuCl4-(aq)
Calculate the value of K for this reaction at 25°C.

Galvanic cell is based on the following half-reactions:

Cu2++2e-Cu(s)E0=0.34VV2++2e-V(s)E0=-1.20V

In this cell, the copper compartment contains a copper electrode and [Cu2+] = 1.00 M, and the vanadium compartment contains a vanadium electrode and V2+ at an unknown concentration. The compartment containing the vanadium (1.00 L of solution) was titrated with 0.0800 MH2EDTA2-, resulting in the reaction

H2EDTA2-(aq)+V2+(aq)VEDTA2-(aq)+2H+(aq)

The potential of the cell was monitored to determine the stoichiometric point for the process, which occurred at a volume of 500.0 mL of H2EDTA2- solution added. At the stoichiometric point, Ecell was observed to be 1.98 V. The solution was buffered at a pH of 10.00.

a. Calculate Ecell before the titration was carried out.

b. Calculate the value of the equilibrium constant Kfor the titration reaction.

c. Calculate Ecell at the halfway point in the titration.

How long will it take to plate out each of the following with a current of 100.0 A?
a. 1.0 kg of Al from aqueous Al3+
b. 1.0 g of Ni from aqueous Ni2+
c. 5.0 moles of Ag from aqueous Ag+

Calculate E° for the following half-reaction:
AgI(s)+e-Ag(s)+I-
(Hint: Reference the Ksp value for Agl and the standard
reduction potential for Ag+.)

Explain the following relationships: AG and w, cell potential and w, cell potential and AG, cell potential and Q.Using these relationships, explain how you could make acell in which both electrodes are the same metal and both solutions contain the same compound, but at different concentrations. How could this cell run spontaneously?

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