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Use the MO model to explain the bonding in BeH2. When constructing the MO energy-level diagram, assume that the Be 1s electrons are not involved in bond formation.

Short Answer

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The molecular orbitals for BeH2 are formed from the two hydrogen 1s orbitals and the 2s and one of the 2p orbitals from beryllium. Overlapping of hydrogen 1s orbital with a beryllium 2s orbital results in formation of one of the sigma bonds. Let us assume that the linear BeH2 molecules has the z axis as the internuclear axis. The 2pz orbital from beryllium has proper symmetry to overlap with the 1s orbitals from hydrogen. But the 2px and 2py orbitals are nonbonding orbitals. These orbitals don’t have proper symmetry.

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01

Explanation

The molecular orbitals for BeH2 are formed from the two hydrogen 1s orbitals and the 2s and one of the 2p orbitals from beryllium. Overlapping of hydrogen 1s orbital with a beryllium 2s orbital results in formation of one of the sigma bonds. Let us assume that the linear BeH2 molecules has the z axis as the internuclear axis. The 2pz orbital from beryllium has proper symmetry to overlap with the 1s orbitals from hydrogen. But the 2px and 2py orbitals are nonbonding orbitals. These orbitals don’t have proper symmetry.

02

Energy-level Diagram

The MO diagram for BeH2 is as follows:

Bond order = (4 - 0)/2 = 2. From the MO diagram it can be predicted that BeH2 is the stable species and is diamagnetic.

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Most popular questions from this chapter

The sp2hybrid atomic orbitals have the following general form:

role="math" localid="1663746599823" ϕ1=13ϕs+2pxϕ2=13ϕs-2px+pyϕ3=13ϕs-2px-py

where, Φs,Φpxandrole="math" localid="1663746751426" Φpyrepresent orthonormal (normalized and orthogonalized) atomic orbitals. Calculate the values of Aand B.

In exercise 71 in chapter 13 the lewis structure for benzene was drawn. Using one of the lewis structures estimate Hffor C6H6(g). Using bond energies and given standard enthalpies of formation of C(g) is 717kJ/mol. The experimental Hffor C6H6is 83 kJ/mol. Explain the discrepancy between the experimental value and the calculated Hfvalue of C6H6(g).

The diatomic molecule OH exist in the gas phase. OH plays an important role in combustion reaction and is a reactive oxidizing agent in polluted air. The bond length and bond energy have been measured to be 97.06 pm and 424.7 kJ/mol, respectively. Assume that the OH molecule is analogous to the HF molecule discussed in the chapter and that the MOs result from the overlap of pz orbital from oxygen and 1s orbital of hydrogen. (The O-H bond lies along the z-axis)

a. Draw a picture of the sigma bonding and antibonding molecular orbitals in OH.

b. Which of the two MOs has the greater hydrogen 1s character?

c. Can the 2px orbital of oxygen form MOs with 1s orbital of hydrogen? Explain.

d. Knowing that only the 2p orbitals of oxygen interact significantly with the 1s orbital of hydrogen, complete the MO diagram for OH. Place the correct number of electrons in the energy level.

e. Estimate the bond order for OH

f. Predict whether the bond order of OH+ is greater than, lesser than, or the same as that of OH+. Explain.

Values of measured bond energies may vary greatly depending on the molecule studied. Consider the following reactions:

NCl3(g)NCl2(g)+Cl(g)ΔH=375kJ/molONCl(g)NO(g)+Cl(g)ΔH=158kJ/mol
Rationalize the difference in the values ofΔHfor these reactions, even though each reaction appears to involve the breaking of only one N-Cl bond. (Hint: Consider the bond order of the NO bond in ONCl and in NO.)

What are molecular orbitals? How do they compare with atomic orbitals? Can you tell by the shape of bonding orbitals and antibonding orbitals which is lower in energy? Explain.

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