Chapter 14: Q50E (page 599)
Consider the following electron configuration. Give four species that in theory, would have this electron configuration .
Short Answer
Four species with this electron configuration are
Chapter 14: Q50E (page 599)
Consider the following electron configuration. Give four species that in theory, would have this electron configuration .
Four species with this electron configuration are
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Get started for freeValues of measured bond energies may vary greatly depending on the molecule studied. Consider the following reactions:
Rationalize the difference in the values offor these reactions, even though each reaction appears to involve the breaking of only one N-Cl bond. (Hint: Consider the bond order of the NO bond in ONCl and in NO.)
Complete the Lewis structures of the following molecules. Predict the molecular structure, polarity, bond angles, and hybrid orbitals used by the atoms marked by asterisks for each molecule.
Cholesterol has the following structure
In such shorthand structures, each point where lines meet represents a carbon atom and most H atom are not shown. Draw the complete structure showing all carbon and hydrogen atom (There will be four bonds to each carbon atom). Indicate which carbon atoms use sp2or sp3 hybrid orbital. Are all carbon atoms in the same plane as implied by the structure?
Question: How does molecular orbital theory explain the following observations?
a. H2 is stable, whereas He2 is unstable.
b. B2 and O2 are paramagnetic, whereas C2 , N2and F2 are diamagnetic.
c. N2 has a very large bond energy associated with it.
d. NO+ is more stable than NO- .
The NMR spectra on the right are for the organic compounds C6H12 and C4H10O. Deduce the structures for these compounds. See Exercise 74 for a discussion of the bonding in organic compounds. The structure of C6H12 has one double bond, with the rest being single bonds, and the structure of C4H10O has only single bonds. Note that the TMS reference has been omitted in each spectrum.
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