Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Ammonia forms hydrogen-bonding intermolecular forces resulting in an unusually high boiling point for a substance with the small size ofNH3. Can hydrazine (N2H4) also form hydrogen-bonding interactions?

Short Answer

Expert verified

As hydrazine may create a hydrogen bond, this connection is strong enough to raise the boiling point of hydrazine.

Step by step solution

01

Concept Introduction

A hydrogen bond is an electrical attraction between a hydrogen atom covalently bonded to a more electronegative atom or group and another electronegative atom with a single pair of electrons.

02

Can hydrazine form hydrogen-bonding interactions

On the molecule of hydrazine (N2H4), it is composed of two atoms of nitrogen and four atoms of hydrogen. Here, thehydrogen and nitrogen are bonded together. And the two nitrogen atoms are also bonded with each other.

Here, the bond of two nitrogen atoms cannot form a hydrogen bond since it is nonpolar. But on the side of the bondsbetween nitrogen and hydrogen, there will be a significant electronegativity difference that will make them polar. Sincethe atoms has a small amount of electronegativity difference, therefore, it will enable the hydrogen bond.

Therefore, since hydrazine can form a hydrogen bond, this bond will be strong enough to make hydrazine's boiling point high.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Small quantities of hydrogen gas can be prepared in the laboratory by the addition of aqueous hydrochloric acid to metallic zinc.

Zns+2HClaqโ†’ZnCl2aq+H2g

Typically, the hydrogen gas is bubbled through water for collection and becomes saturated with water vapor. Suppose 240. mL of hydrogen gas is collected at 30.oC and has a total pressure of 1.032 atm by this process. What is the partial pressure of hydrogen gas in the sample? How many grams of zinc must have reacted to produce this quantity of hydrogen? (The vapor pressure of water is 32 torr at 30oC.)

Question:Indium oxide contains 4.784 g of indium for every 1.000 g of oxygen. In 1869, when Mendeleevfirst presented his version of the periodic table, he proposed the formula In2O3 for indium oxide.Before that time, it was thought that the formula was InO. What values for the atomic mass ofindium are obtained using these two formulas? Assume that oxygen has an atomic mass of16.00.

Oil of wintergreen, or methyl salicylate, has the following structure:

Methyl 4-hydroxybenzoate is another molecule with exactly the same molecular formula; it has the following structure:

Account for the large difference in the melting points of the two substances.

Question 65: The reactionis expected to obey the mechanism .


Write the rate law for this reaction.

The reaction 2NO(g)+O2โ†’2NO2(g)was studied, and the following data were obtained,

Where,Rate=-d[O2]dt.

[NO]0(molecules/cm3)
[O2]0(molecules/cm3)
role="math" localid="1663754227568" InitialRate(molecules-3s-1)
1.0ร—1018
1.0ร—1018
role="math" localid="1663754491156" 2.00ร—1016
3.0ร—1018
1.0ร—1018
1.80ร—1017
2.5ร—1018
2.5ร—1018
3.13ร—1017

What would be the initial rate for an experiment where

[NO]0=6.21x1018molecules/cm3and[O2]0=7.35x1018molecules/cm3 ?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free