Question

The complex ion $\mathit{R}\mathit{u}{{\mathbf{\left(}\mathbf{\text{Phen}}\mathbf{\right)}}_{\mathbf{3}}}^{\mathbf{2}\mathbf{+}}$has been used as probe for the structure of DNA. (Phen is a bidentate ligand.)

a. What type of isomerism is foundin $\mathit{R}\mathit{u}{{\mathbf{\left(}\mathbf{\text{Phen}}\mathbf{\right)}}_{\mathbf{3}}}^{\mathbf{2}\mathbf{+}}$?

b. $\mathit{R}\mathit{u}{{\mathbf{\left(}\mathbf{\text{Phen}}\mathbf{\right)}}_{\mathbf{3}}}^{\mathbf{2}\mathbf{+}}$is diamagnetic ( as all complexes of ${\mathbf{\text{Ru}}}^{\mathbf{2}\mathbf{+}}$). Draw the crystal field diagram for the d orbitals in this complex ion.

$\mathbf{\text{Phen=1,10=-phenanthroline=}}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}$

Short answer

Optical isomers are compounds having the same number and kinds of bonds and different spatial arrangements. They are non-identical mirror images of each other.

Step-by-step solution

a) Isomerism

$\text{Ru}{{\left(\text{phen}\right)}_3}^{2+}$has optical isomers

b) Crystal Field Diagram

As Ru is a 4d transition metal, all of its complexes should be diamagneticCFT diagrams of d orbitals of ${\text{Ru}}^{2+}$