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The space filling model of hydrogen cyanide and phosgene are shown below:

Use LE model to describe the bonding in hydrogen cyanide and phosgene.

Short Answer

Expert verified

Firstly the Lewis structure is drawn and then the orientation of the atoms is determined using the VSEPR model. The Lewis structure of hydrogen cyanide is drawn below.

The carbon and the nitrogen is sphybridized. The structure is linear.

The Lewis structure of phosgene is given below.

The carbon is sp2hybridized and the structure has trigonal planar geometry.

Step by step solution

01

Localised electron Model Of hydrogen cyanide

The Lewis structure of hydrogen cyanide is as follows

The carbon and the nitrogen is sphybridized. The atoms are arranged linearly. Nitrogen has two sp hybrid orbitals. One sp orbital forms a sigma bond with carbon and the other sp orbital houses the lone pair of electron. The unhybridized orbital forms the two pi bonds. One of the two sp orbital of the carbon participates in sigma bonding with the nitrogen while the other participates in sigma bonding with hydrogen.

02

Localised electron model of phosgene

The Lewis structure of phosgene is given below.

The central carbon is sp2 hybridized. The arrangement of electrons is in trigonal planar form. The oxygen is sp2 hybridized. Out of the three hybrid orbitals, two orbitals participate in sigma bonding with chlorine and the other one forms sigma bond with the oxygen. The unhybridized p orbital helps in forming the pi bond between carbon and oxygen. The other two sp2 hybrid orbitals of oxygen house the two lone pairs of electrons.

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Most popular questions from this chapter

The rate constant for the gas-phase decomposition of N2O5.

N2O5โ€Šโ€Šโ†’โ€Šโ€Š2NO2โ€Šโ€Š+โ€Šโ€Š12โ€ŠO2

It has the following temperature dependence:

Make the appropriate graph using this data, and determine

the activation energy for this reaction.

The reaction 2NO(g)+O2โ†’2NO2(g)was studied, and the following data were obtained,

Where,Rate=-d[O2]dt.

[NO]0(molecules/cm3)
[O2]0(molecules/cm3)
role="math" localid="1663754227568" InitialRate(molecules-3s-1)
1.0ร—1018
1.0ร—1018
role="math" localid="1663754491156" 2.00ร—1016
3.0ร—1018
1.0ร—1018
1.80ร—1017
2.5ร—1018
2.5ร—1018
3.13ร—1017

What would be the initial rate for an experiment where

[NO]0=6.21x1018molecules/cm3and[O2]0=7.35x1018molecules/cm3 ?

The following data were collected in two studies of the

reaction

2A + B โ†’ C + D

Where

In experiment 1, [B]0 = 5.0 M. In experiment 2, [B]0 =10.0 M.

a. Why is [B] much greater than [A]?

b. Give the rate law and value for kfor this reaction.

c. Which of the following mechanisms could be correct for this reaction? Justify your choice.

i. A+B โ†” E (fast equilibrium)

E + B โ†” C + D (slow)

ii. A + B โ†” E (fast equilibrium)

E + A โ†” C + D (slow)

iii. A + A โ†” E (slow)

E + B โ†” C + D (fast)

Consider the following representation of the reaction2NO2(g)โ†’2NO(g)+O2(g).

Determine the time for the final representation below ifthe reaction is

a. first order

b.second-order

c.zero-order

X-rays of wavelength 2.63ร…were used to analyze a crystal. The angle of first-order diffraction (n=1 in the Bragg equation) was 15.55ยฐ. What is the spacing between crystal planes, and what would be the angle for second-order diffraction (n=2)?

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