Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The type of rate law for a reaction, either the differential rate law or the integrated rate law, is usually determined by which data is easiest to collect. Explain.

Short Answer

Expert verified

The reaction rate is the measure of the change of concentration of reactants or products during the progression of a chemical reaction. Different rate laws are used to explain the reaction progress. These rate laws are expressed as mathematical relationships between different parameters

Step by step solution

01

Determine the differential rate law or integrated rate law. 

Differential rate law and integrated rate law are two forms of rate laws. The key difference between differential rate law and integrated rate law is that differential rate law gives the rate of a chemical reaction as a function of the change in concentration of one or more reactants during a particular time period, whereas integrated rate law gives the rate of a chemical reaction as a function of the initial concentration of one or more reactants after a specific period of time.

02

Determine the differential rate law equation

The differential rate law for the below chemical reaction can be given as a mathematical expression.

A → B + C

Rate = – {d[A] / dt} = k[A]n

Here, [A] is the concentration of reactant “A” and “k” is the rate constant. “n” gives the order of reaction. The differential rate law equation can be integrated to obtain a clear relationship between [A] and time “t”. This integration gives the integrated rate law.

03

Determine the integrated rate law equation

For the chemical reaction A → B + C, integrated rate law can be expressed as a mathematical expression as given below.

ln[A] = -kt + ln[A]0

Here, [A]0 is the initial concentration of the reactant A and [A] is the concentration of reactant “A” after “t” time has passed. However, integrated rate laws are different from each other based on the order of the reaction “n”. The above equation is given for zero order chemical reactions.

For first order reactions, the rate law equation is,

[A] = [A]e-kt

For second order reactions, the rate law equation is,

1/[A] = 1/[A]0 + kt

In order to determine the rate constant of a reaction, above equations can be used as follows.

For first order reactions,

k=In[A]InA0/t

For second order reactions,

k=1/[A]1/[A]0/t

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following results were obtained at 600 k for the decomposition of ethanol on an alumina (Al2O3) surface,

C2H5OH(g) → C2H4(g) + H2O(g)

a. Predict Ptotal in torr at t=80s

b. What is the value of the rate constant, and what are its units?

c. what is the order of the reaction?

d. Calculate Ptotal at t = 300s.

4.32×104At 40oC,H2O2(aq)will decompose according to the following reaction:

2H2O2(aq)2H2O(l)+O2(g)

The following data were collected for the concentration of role="math" localid="1663758207149" H2O2at various times.

Time (s)[H2O2](mol/L)
01.00

role="math" localid="1663758266765" 2.16×104

0.500

4.32×104

0.250

a. Calculate the average rate of decomposition of H2O2between and 2.16×104. Use this rate to calculate the average rate of production of O2gover the same time period.b. What are these rates for the time period 2.16×104to 4.32×104?

Consider the hypothetical reaction A+B+2C2D+3Ewhere the rate law is

An experiment is carried out where[A]0=1.0×10-2M

,[B]0=3.0M and[C]0=2.0M. The reaction is started and after seconds, the concentration of A is3.8×10-3M.

(a) Calculate the value offor this reaction.

(b) Calculate half-life for this experiment.

(c) Calculate concentration of A after 13.0seconds.

(d) Calculate the concentration of Cafter 13.0seconds.

Two isomers (A and B) of a given compound dimerize as follows:

2A→A2

2B→B2

Both processes are known to be second order in the reactant, and k1 is known to be 0.250 L mol-1s-1 at 25˚ C. In a particular experiment A, and B were placed in separate containers at 25˚C, where [A]˳=1.00×10-2 M and [B]˳=2.50×10-2 M. After each reaction had progressed for 3.00 min, [A]=3.00[B]. In this case the rate laws are defined as follows:

a. Calculate the concentration of A2 after 3.00 min.

b. Calculate the value of k2.

c. Calculate the half-life for the experiment involving A.

The reaction 2NO(g)+Cl2(g)2NOCl(g)was studied at-10oC. The following results were obtained, whereRate=-d[Cl2]dt.

[NO]0(mol/L)
[Cl2]0(mol/L)
Initial Rate(molL-1min-1)
0.100.10
0.18
0.100.20
0.36
0.20
0.20
1.45

a. What is the rate law?

b. What is the value of the rate constant?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free