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Write expressions for K and Kp for the following reactions.

a. 2NH3(g)+CO2(g)N2CH4O(s)+H2O(g)

b. 2KClO3(s)2KCl(s)+3O2(g)

c. 2KClO3(s)2KCl(s)+3O2(g)

d. CuO(s)+H2(g)Cu(l)+H2O(g)

Short Answer

Expert verified

a.K =H2ONH32CO2 and Kp=PH2OPNH32PCO2

b.K =N2Br23 and Kp=PN2PBr23

c.K =O23 and Kp=PO23

d. K =H2OH2and Kp=PH2OPH2

Step by step solution

01

Subpart a)

We know that the activities of pure liquids and solids are 1. Therefore, we neglected them in the equilibrium constant expressions.

The given balanced chemical equation is shown below:

2NH3g+CO2(g)N2CH4Os+H2Og

The expression for the equilibrium constant, K in terms of concentrations is written below:

Kp=PH2OPNH32PCO2

The expression for the equilibrium constant, Kp in terms of partial pressures is written below:

Kp=PH2OPNH32PCO2

02

Subpart b) 

The given balanced chemical equation is shown below:

2NBr3sN2g+ 3Br2g

The expression for the equilibrium constant, K in terms of concentrations is written below:

K =N2Br23

The expression for the equilibrium constant, Kp in terms of partial pressures is written below:

Kp=PN2PBr23

03

Subpart c)

The given balanced chemical equation is shown below:

2KClO3s2KCls+ 3O2g

The expression for the equilibrium constant, K in terms of concentrations is written below:

K =O23

The expression for the equilibrium constant, Kp in terms of partial pressures is written below:

Kp=PO23

04

Subpart d)

The given balanced chemical equation is shown below:

CuOs+H2gCul+H2Og

The expression for the equilibrium constant, K in terms of concentrations is written below:

K =H2OH2

The expression for the equilibrium constant, Kp in terms of partial pressures is written below:

Kp=PH2OPH2

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