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Question: Explain the difference between K, Kp, and Q.

Short Answer

Expert verified

In the equilibrium reaction, the Q value is calculated for both initial conditions and equilibrium conditions, while the K and Kp values are calculated for only equilibrium conditions.

Step by step solution

01

Write the expressions for K, Kp, and Q

Consider a general chemical reaction as shown below:

mM+nNqQ+rR...1

Here,

M and N are the reactant species.

Q and R are the product species.

m, n, q, and r are the coefficients of M, N, Q, and R, respectively.

According tothe law of mass action, the equilibrium constant expressions for the above reaction at equilibrium can be represented as follows:

For K in terms of concentrations:

K=QqRrMmNn ...(2)

For Kp in terms of partial pressures:

Kp=PQqPRrPMmPNn ...(3)

The expression for the reaction quotient, Q, for this reaction is shown below:

Q=QqRrMmNn ...(4)

02

The difference between K, Kp, and Q are described.

Q is the reaction quotient, whereas K and Kp are equilibrium constants. All are calculated by the law of mass action. Q is used for any set of conditions, while K and Kp are used for equilibrium conditions only. The reaction quotient becomes the equilibrium constant when the reaction is at equilibrium. The equilibrium constant value does not change for the equilibrium reaction at a specific temperature, but the reaction quotient value changes with changing the reaction conditions.

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Most popular questions from this chapter

Consider an initial mixture of N2 and H2 gases that can be represented as follows.

The gases react to form ammonia gas (NH3) as represented by the following concentration profile.

a. Label each plot on the graph as N2, H2, or NH3 and explain your answers.

b. Explain the relative shapes of the plots.

c. When is equilibrium reached? How do you know?

The equilibrium constant Kp for the reaction: CCl4(g)C(s)+2Cl(g)

at 7000C is 0.76. Determine the initial pressure of carbon tetrachloride that will produce a total equilibrium pressure of 1.20 atm at 7000C.

Given: Kp = 0.76 P0 = initial pressure of CCl4

The text gives an example reaction for which K = KP. The text states this is true “because the sum of the coefficients on either side of the balanced equation is identical. . . .” What if you are told that for a reaction K = KP, but the sum of the coefficients on either side of the balanced equation is not equal? How is this possible?

You have learned how to treat systems that have small equilibrium constants by making approximations to simplify the math. What if the system has a very large equilibrium constant? What can you do to simplify the math for this case? Use the same example from the text, but change the value of the equilibrium constant to 1.6105 and rework the problem. Why can you not use approximations for the case in which K = 1.6?

Consider the reaction

Fe3+(aq)+SCN-(aq)FeSCN2+(aq)

How will the equilibrium position shift if

a. water is added, doubling the volume?

b. AgNO3aq is added? (AgSCN is insoluble.)

c. NaOH(aq) is added? [FeOH3 is insoluble.]

d. FeNO33aq is added?

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