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The value of the equilibrium constant K depends on which of the following (there may be more than one answer)?

a. the initial concentrations of the reactants

b. the initial concentrations of the products

c. the temperature of the system

d. the nature of the reactants and products Explain.

Short Answer

Expert verified

You need to explain which condition will affect the equilibrium condition.

Step by step solution

01

Solution of the problem

Answer of the problem is option ‘c’ and ‘d’.

02

Explanation of the solution

As you know, equilibrium constant is a function of temperature. It also depends on the nature of reactants and products.

Again equilibrium constant depends on the concentration of reactants and products at equilibrium position not on the initial concentrations.

03

Conclusion

You can attain the equilibrium position in several pathways. Therefore, one condition is no enough to explain its dependency. You need sets of conditions.

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Most popular questions from this chapter

Consider the reaction

A(g)+B(g)C(g)+D(g)

A friend asks the following: “I know we have been told that if a mixture of A, B, C, and D is at equilibrium and more of A is added, more C and D will form. But how can more C and D form if we do not add more B?” What do you tell your friend?

Consider the decomposition equilibrium for dinitrogenpentoxide:

2N2O5(g)4NO2(g)+O2(g)

At a certain temperature and a total pressure of1.00 atm, the N2O5 is 0.50% decomposed (by moles)at equilibrium.

a. If the volume is increased by a factor of 10.0, willthe mole percent of N2O5 decomposed at equilibrium be greater than, less than, or equal to 0.50%?Explain your answer.

b. Calculate the mole percent of N2O5 that will bedecomposed at equilibrium if the volume isincreased by a factor of 10.0

Which of the following statements is(are) true? Correct the false statement(s).

a. When a reactant is added to a system at equilibrium at a given temperature, the reaction will shift right to reestablish equilibrium.

b. When a product is added to a system at equilibrium at a given temperature, the value of K for the reaction will increase when equilibrium is reestablished.

c. When temperature is increased for a reaction at equilibrium, the value of K for the reaction will increase.

d. Addition of a catalyst (a substance that increases the speed of the reaction) has no effect on the equilibrium position.

A 4.72-g sample of methanol (CH3OH) was placed in an otherwise empty 1.00-L flask and heated to 250.0C to vaporize the methanol. Over time the methanol vapor decomposed by the following reaction:

CH3OH(g)CO(g)+2H2(g)

After the system has reached equilibrium, a tiny hole is drilled in the side of the flask allowing gaseous compounds to effuse out of the flask. Measurements of the effusing gas show that it contains 33.0 times as much H2(g) as CH3OH(g). Calculate K for this reaction at 250.0C.

A sample of S8(g) is placed in an otherwise empty, rigid container at 1325 K at an initial pressure of 1.00 atm, where it decomposes to S2(g) by the reaction

S8(g)4S2(g)

At equilibrium, the partial pressure of S8 is 0.25 atm.Calculate Kp for this reaction at 1325 K.

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