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Consider an initial mixture of N2 and H2 gases that can be represented as follows.

The gases react to form ammonia gas (NH3) as represented by the following concentration profile.

a. Label each plot on the graph as N2, H2, or NH3 and explain your answers.

b. Explain the relative shapes of the plots.

c. When is equilibrium reached? How do you know?

Short Answer

Expert verified

a. In the given graph, each plot is labelled as shown in Step 1.

b. The relative shapes of the plots are explained in Step 2.

c. When the reaction is reached to equilibrium, the rate of the forward reaction equals the rate of the reverse reaction.

Step by step solution

01

Step 1:

In the given graph, each plot is labelled as shown below:


The given initial mixture contains two nitrogen molecules and six hydrogen molecules. There are no ammonia present at initially. The ratio of hydrogen to nitrogen is 3:1 in the reaction mixture before the reaction starts. So, the line with the greatest initial concentration must be the H2 plot. In the graph, the green curve has the highest one. Hence, the green curve is labelled as H2.

The blue curve has the lowest initial concentration. So, it should be the N2 plot. Hence, the blue curve is labelled as N2.

The pink curve begins from the origin of the graph which indicates the initial concentration is zero before the reaction starts. So, it must be the NH3 plot. Hence, the pink curve is labelled as NH3.

02

Step 2:

The balanced chemical equation for the formation of ammonia from the gases of hydrogen and nitrogen as shown below:

N2g+3H2g2NH3g

According to the above balanced equation, 1 equivalent of nitrogen needs three equivalents of hydrogen to give two equivalents of ammonia. So, the concentration of hydrogen decreases three times faster than that of nitrogen as seen in the graph. This is due to the stoichiometric ratio of hydrogen to nitrogen that is 3:1 in the balanced equation. At the same time, the production of ammonia increases two times faster than nitrogen because the mole ratio of ammonia to nitrogen is 2:1 in the balanced equation.

03

Step 3:

When the rate of the forward reaction equals the rate of the reverse reaction, equilibrium is established. Because no net change in any of the reactant or product concentrations has occurred at this point, the different graphs indicate that equilibrium has been attained when their concentrations no longer fluctuate with time.

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Most popular questions from this chapter

A sample of solid ammonium chloride was placed in an evacuated chamber and then heated, causing it to decompose according to the following reaction:

NH4Cl(s)โ†’NH3(g)+HCl(g)

In a particular experiment, the equilibrium partial pressure of NH3(g)

in the container was 2.9 atm. Calculate the value ofKp for the decomposition of NH4Cl(s)at this temperature.

At 2200oC, K = 0.050 for the reaction

N2(g)+O2(g)โ‡Œ2NO(g)

What is the partial pressure of NO at equilibrium assuming the N2 and O2 had initial pressures of 0.80 atm and 0.20 atm, respectively?

For the reaction

NH3(g)+H2S(g)โ‡ŒNH4HS(s).

. at 35.00C. If 2.00 moles each of NH3, H2S, andNH4HS are placed in a 5.00-L vessel, what mass ofNH4HS will be present at equilibrium? What is the pressure of H2S at equilibrium?

Consider the following generic reaction:

2A2Bgโ†’2A2g+B2g

Some molecules of A2B are placed in a 1.0-L container. As time passes, several snapshots of the reaction mixture are taken as illustrated below.

Which illustration is the first to represent an equilibrium mixture? Explain. How many molecules of A2B were initially placed in the container?

Nitric oxide and bromine at initial partial pressures of 98.4 torr and 41.3 torr, respectively, were allowed to react at 300. K. At equilibrium the total pressure was 110.5 torr. The reaction is

2NO(g)+Br2(g)โ†’2NOBr(g)

a. Calculate the value ofKp.

b. What would be the partial pressures of all species if NOand,Br2both at an initial partial pressure of 0.30 atm, were allowed to come to equilibrium at this temperature?

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