Question

Use the following data to estimate∆H_i for barium bromide.

Ba(s) + Br₂(g)→BaBr₂(g)

Lattice energy -1985 kJ/mol

First ionization energy of Ba 503 kJ/mol

Second ionization energy of Ba 965 kJ/mol

Electron affinity of Br -325 kJ/mol

Bond energy of Br₂ 193 kJ/mol

Enthalpy of sublimation of Ba 178 kJ/mol

Short answer

The∆H_iof barium bromide is 278 KJ/mol.

Step-by-step solution

Definition of  the ∆Hf

The amount of heat released or absorbed when a mole of a compound gets formed from its constituent elements, every substance being in its normal physical state.

– Determining value of ∆Hi For BaBr2

Barium bromide is the chemical compound with the formula BaBr₂. Like barium chloride, it dissolves well in water and is toxic.

Given:

Lattice energy -1985 kJ/mol

First ionization energy of Ba 503 kJ/mol

Second ionization energy of Ba 965 kJ/mol

Electron affinity of Br -325 kJ/mol

Bond energy of Br2 193 kJ/mol

Enthalpy of sublimation of Ba 178 kJ/mol

To calculate ∆Hi for barium bromide we will use the following relation,

$∆H_i$=

∆H_i= (E _lattice +1st ∆Hi +2nd ∆Hi+ E_affinity+ Bond energy + E_sub.)

= (-1985+503+965-325+386+178) kJ/mol

= 278 kJ/mol.