Question

Question: How many unpaired electrons are present in each of the first row transition metals in the ground state?

Short answer

The number of valence electrons present in Scandium$\left(\mathrm{Sc}\right)$, Titanium$\left(\mathrm{Ti}\right)$, Vanadium$\left(\mathrm{V}\right)$, chromium$\left(\mathrm{Cr}\right)$, Iron$\left(\mathrm{Fe}\right)$, Cobalt$\left(\mathrm{Co}\right)$, Nickel$\left(\mathrm{Ni}\right)$, Copper$\left(\mathrm{Cu}\right)$ and Zinc$\left(\mathrm{Zn}\right)$ are$1,2,3,6,5,4,3,2,1,0$ .

Step-by-step solution

Step 1:

In the first row of transition metals, the ten elements that can be found are: Scandium (Sc), Titanium (Ti), Vanadium (V), chromium (Cr), Iron (Fe), Cobalt (Co), Nickel (Ni), Copper (Cu) and Zinc (Zn).

Step 2:

Metal Electronic Configuration

Sc $\left[\mathrm{Ar}\right]4s^{2}3d^1$

Ti $\left[\mathrm{Ar}\right]4s^{2}3d^2$

V $\left[\mathrm{Ar}\right]4s^{2}3d^3$

Cr $\left[\mathrm{Ar}\right]4s^{1}3d^5$

Mn $\left[\mathrm{Ar}\right]4s^{2}3d^5$

Fe $\left[\mathrm{Ar}\right]4s^{2}3d^6$

Co $\left[\mathrm{Ar}\right]4s^{2}3d^7$

Ni $\left[\mathrm{Ar}\right]4s^{2}3d^8$

Cu $\left[\mathrm{Ar}\right]4s^{1}3d^{10}$

Zn $\left[\mathrm{Ar}\right]4s^{2}3d^{10}$