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The bond energy for theC-Hbond is about 413kJ/molin CH4 but 380kJ/mol in CHBr3. Although these values are relatively close in magnitude, they are different. Explain why they are different. Does the fact that the C-Hbond energy in CHBr3is lower make any sense? Why?

Short Answer

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Answer

TheC-Hbond in bromoform is unstable due to the electronegativity of Br. Thesigma bond electron density is minimized. So, theC-Hbond breaks.

Step by step solution

01

Describing theC-H bond energy in the methane molecule

The energy needed in a bond formation varies irregularly.The process of bond formation takes place in a clear way.

Process Energy required

CH4(g)CH3(g)+H(g) 435

CH3(g)CH2(g)+H(g) 453

CH2(g)CH(g)+H(g) 425

CH(g)CH(g)+H(g) 339

Total = 1652kJ/mol

Average = 1652 / 4 = 413

The average has been taken to calculate theC-Hbond energy.

02

Describing the C-H  bond energy

The average of bond energy is used as a better method even though we assume the approximation of the energy correlation with theC-Hbond.

The energy needed to break the C-H bond in methane =413 kJ/mol

The energy needed to break the C-Hbond in methane =380kJ/mol

The degree of sensitivity of the bondcan be calculated by the experimental value of the energy required for the C-Hbond.

The stronger bond requires a larger amount of energy. Thus, methane has a stronger bond while bromoform does not.

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