Question

Rank the following bonds in order of increasing ionic character:

$\mathit{N}\mathbf{-}\mathbf{0}\mathbf{,}\mathit{C}\mathit{a}\mathbf{-}\mathit{O}\mathbf{,}\mathit{C}\mathbf{-}\mathit{F}\mathbf{,}\mathit{B}\mathit{r}\mathbf{-}\mathit{B}\mathit{r}\mathbf{,}\mathit{K}\mathbf{-}\mathit{F}$

Short answer

Answer

The increasing order of ionic character: Br-Br < N-O < C-F < Ca-O < K-F.

Step-by-step solution

Step 1.  Dependency of ionic character

Ionic character depends on the difference in electronegativity. More the difference, more the ionic character.

Step 2. Writing electronegativity of each required element

Electronegativities of N, O, Ca, C, F, Br and K are 3.04, 3.44, 1, 2.55, 3.98, 2.96 and 0.82 respectively.

Step 3. Finding the difference between the electronegativity

$$\begin{gathered} N-O3.44-3.04=0.04 \\ Ca-O3.44-1=2.44 \\ C-F3.98-2.55=1.43 \\ Br-Br2.96-2.96=0 \\ K-F3.98-0.82 \end{gathered}$$