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Arrange the following molecules from most to least polar, and explain your order: CH4, CF2Cl2, CF2H2, CCl4, and CCl2H2.

Short Answer

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Answer

The arrangement of molecules from least polar to most polar is given as follows

CF2H2 > CCl2H2 > CF2Cl2 > CH4 = CCl4

Step by step solution

01

 Describing the dipole moment

This is defined as thepolarity of atoms/ions within a molecule in acovalent/ionic bond. The dipole moment depends upon theelectronegativity of the atom.

The difference in electronegativity produces the dipole moment. The more the difference in electronegativity more will be dipole moment. This also depends oncharge separation.

02

Describing the order of the polarity within the molecules

These molecules' dipole moment isdefinedby the lewis structure which showselectronegativity and polarity inside the molecule.

In CF2H2 molecule has the highest dipole moment and CH4 and CCl4equally have the least.

CF2H2 > CCl2H2 > CF2Cl2 > CH4 = CCl4

CF2H2is more electronegative than CCl2H2 because F is more electronegative than Cl.

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Most popular questions from this chapter

An alternative definition of electronegativity is Electronegativity = constant (I.E. - E.A.), where I.E. is the ionization energy and E.A. is the electron affinity using the sign conventions of this book. Use data in Chapter 12 to calculate the (I.E. - E.A.) term for F, Cl, Br, and I. Do these values show the same trend as the electronegativity values given in this chapter? The first ionization energies of the halogens are 1678, 1255, 1138, and 1007 kJ/mol, respectively. (Hint:Choose a constant so that the electronegativity of fluorine equals 4.0. Using this constant, calculate relative electronegativities for the other halogens and compare to values given in the text.)

Consider the following energy changes

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You and a friend are studying for a chemistry exam. What if your friend tells you that all molecules with polar bonds are polar molecules? How would you explain to your friend that this is not correct? Provide two samples to support your answer.

Question:Consider the following bond lengths: Cโ€“O is 1.43 ร…, C=O is 1.23 ร…, and Cโ‰กO 1.09 ร… In theion, all three C-O bonds have identical bond lengths of 1.36 ร…. Why?

Give two requirements that should be satisfied for a molecule to be polar. Explain why CF4 and KrF4are nonpolar compounds (have no net dipole moments), whereas SF4is polar (has a net dipole moment). Is CO2polar? What about COS? Explain.

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