Question

Q.19. A reaction of 1 L of chlorine gas (Cl₂) with 5 L of fluorine gas (F₂) yields 2 L of a gaseous product. All gas volumes are at the same temperature and pressure. What is the formula of the gaseous product?

Short answer

Answer

The formed product is two moles of CIF₅.

Step-by-step solution

Step-by-Step SolutionStep 1: Given information

Take the reaction in which 1L of chlorine reacts with 5 L of fluorine to get 2L of gaseous product. Chlorine and fluorine combine to form a gaseous product.

Statement of Gay Lussac's Law

The law states that the constant pressure and temperature react in which volume gives a simple ratio.Take examples: One volume and 3 volumes reacted to form two volumes.

N₂ + 3H₂ $\underset{}{\overset{}{\to }}$2NH₃

Here, one volume of nitrogen reacted with three volumes of Hydrogen will yield two ammonia volumes. This holds a volume ratio of 1:3.

Statement of Avogadro's Law

The law states that the same gas volume has the same number of molecules at constant pressure and temperature. The mathematical relationship can be denoted as:

V$\alpha$n

Gas volume is directly proportional to the mole's number at the same pressure and temperature.

Product formation using the example at the same temperature and pressure

According to the law of Gay Lussac, fluorine and chlorine hold a ratio of volume as 1:5. It can be denoted as:

Cl₂ + 5F₂$\underset{}{\overset{}{\to }}$ Product

The reaction can be written using Avogadro's law:

Cl_{2 (g)} + 5F_{2 (g)}$\underset{}{\overset{}{\to }}$ 2Cl_xF_y(g)

Cl_{2 (g)} + 5F_{2 (g)} $\underset{}{\overset{}{\to }}$ 2ClF_5(g)

This is the overall reaction, and the formed product is two moles of ClF₅.