Question

Use the following data to calculate the K_sp value for eachsolid.
a. The solubility of CaC₂O₄, is 6.1 x 10^-3 g/L.
b. The solubility of Bil₃ is 1.32 x 10^-5 mol/L.

Short answer

Thevalue of K_sp for each solid can be calculated

Step-by-step solution

Calculation for the solubility CaC2O4

The molar mass of $Ca{C}_2{O}_4=128g/mol$The solubility can be denoted as:

$Solubility=\frac{6.1\times {10}^{-3}g/L}{128mol/L}=4.76\times {10}^{-5}mol/L$

The dissolution equilibrium can be denoted as:

$$\begin{gathered} Ca{C}_2{O}_4\left(s\right)\iff C{a}^{+2}\left(aq\right)+C_2{O_4}^{2-}\left(aq\right) \\ {K}_{sp}=\left[C{a}^{2+}\right]\left[C_2{O_4}^{2-}\right] \\ \left[C{a}^{2+}\right]=smol/L \\ \left[C_2{O_4}^{2-}\right]=smol/L \\ {K}_{sp}=\left[s\right]\left[s\right]=s^2 \\ s=2.27\times {10}^{-9} \end{gathered}$$

Calculation for the solubility Bil3

The dissolution equilibrium can be denoted as:

$$\begin{gathered} Bi{I}_{3\left(s\right)}\iff B{i}^{3+}\left(aq\right)+3I^{-}\left(aq\right) \\ {K}_{sp}=\left[B{i}^{3+}\right]{\left[I^{-}\right]}^3 \\ \left[B{i}^{3+}\right]=smol/L \\ {\left[I^{-}\right]}^3=3smol/L \\ {K}_{sp}=\left[s\right]{\left[3s\right]}^3=27s^4 \\ {K}_{sp}=8.19\times {10}^{-19} \end{gathered}$$