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The following plot shows the pH curves for the titrations of various acids with 0.10 M NaOH (all of the acids were 50.0mL samples of 0.10 M concentration)

  1. Which pH curve corresponds to the weakest acid?
  2. Which pH curve corresponds to the strongest acid?

Which point on the pH curve would you examine to see if this acid is a strong acid or a weak acid (assuming you did not know the initial concentration of the acid)?

c. Which pH curve corresponds to an acid withKa1×10-6?

Short Answer

Expert verified
  1. The pH curve corresponds to the weakest acid is f
  2. The pH curve corresponds to the strongest acid is a
  3. The pH curve corresponds to an acid with Ka1×10-6?is d

Step by step solution

01

Definition of pH curve

The plot of the pH of the analyte solution versus the volume of the titrant added as the titration progresses is defined as a pH curve.

02

Explanation

a. The equivalence point of an acid-base titration can be obtained by the halfway point of the vertical solution of the pH curve. For a strong acid-strong base titration, the equivalence point lies at pH 7.0, and the vertical portion has a wide range. For a weak acid, this vertical portion is narrower than that of a strong acid. Weaker the acid, the narrower the vertical portion. This is because the weaker the acid, the larger its initial pH

According to the given pH curves, the f curve corresponds to the weakest acid.

b. The equivalence point of an acid-base titration can be obtained by the halfway point of the vertical solution of the pH curve. For a strong acid-strong base titration, the equivalence point lies at pH 7.0, and the vertical portion has a wide range.

According to the given pH curves, a curve corresponds to the strongest acids. It has a wider vertical portion, and the halfway point of the vertical portion lies at pH 7.0

When the initial concentration of the acid is unknown, the halfway point of the vertical portion of the pH curve should be examined to see if the acid is a strong or a weak acid.

c. In a weak acid-strong base titration, when OH- is added, the weak acid is consumed, and its conjugate base is formed. At the halfway point of the titration, the concentration of weak acid and concentration of its conjugate base become equal. At this point pH=pKa,

For a weak acid with Ka1×10-6,pH=6.0at the halfway point of the titration. The pH of the halfway point of titration can be obtained from the horizontal portion of the curve.

According to the given pH curves, the curve corresponds to an acid withKa1×10-6 is d.

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Most popular questions from this chapter

Question: Consider the titration of a generic weak acid HA with a strong base that gives the following titration curve:

On the curve indicate the points that correspond to the following.

a. The equivalence point

b. The maximum buffering region

c. pH=pKa

d. pH depends only on [HA]

e. pH depends only on [A]

f. pH depends only on the amount of excess strong base added

One of the most challenging parts of solving acid–base problems is writing out the correct equation. When a strong acid or a strong base is added to solutions, they are great at what they do and we always react them first. If a strong acid is added to a buffer, what reacts with the H1 from the strong acid and what are the products? If a strong base is added to a buffer, what reacts with the OH2 from the strong base and what are the products? Problems involving the reaction of a strong acid or strong base are assumed to be stoichiometry problems and not equilibrium problems. What is assumed when a strong acid or strong base reacts to make it a stoichiometry problem?

Which of the indicators in Fig. 8.8 could be used for doing the titrations in Exercises 64 and 66?

Repeat the procedure in Exercise 67 for the titration of25.0 mL of 0.100 M pyridine (Kb = 1.7 x 10-9) with0.100 M hydrochloric acid. Do not do the points at24.9 mL and 25.1 mL.

Question:Consider the titration of 100.0 mL of 0.100 M H3A(Ka1 = 5.0 x 10-4, Ka2= 1.0 x 10-8, Ka3 = 1.0 X 10-11) with 0.0500 M NaOH.
a. Calculate the pH after 100.0 mL of 0.0500 M NaOHhas been added.
b. What total volume of 0.0500 M NaOH is required toreach a pH of 8.67?

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