Question

What happens to the ${\mathbf{K}}_{\mathbf{sp}}$value of solid as the temperature of the solution changes? Consider both increasing and decreasing temperatures, and explain your answer.

Short answer

For the exothermic process, an increase in temperature shifts the equilibrium towards the reactants.

For the endothermic process, the increase in temperature increases the solubility and the value of the solubility product.

Step-by-step solution

Definition of solubility

Solubility is the property of molecules of the solute and solvent forming a new bond.

Explanations

The reaction for the solubility of salt is represented as

$\text{AX(s)}\rightleftharpoons {\text{M}}^{\text{x+}}\text{(aq)}+{\text{X}}^{\text{x-}}$

For the exothermic process, an increase in temperature shifts the equilibrium towards the reactants. In this case, an increase in temperature decreases the solubility and the solubility product value also decreases.

A decrease in temperature takes place the system to have fewer heat shifts the equilibrium toward products. This temperature decrease increases the solubility and solubility product value of the solid.

For the endothermic process, the increase in temperature increases the solubility and the value of the solubility product. The decrease in temperature decreases the solubility, and the value of the solubility product also decreases.