Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Do all the molecules of a gas strike the walls of their container with the same force? Justify your answer on the basis of the kinetic model of gases.

Short Answer

Expert verified
No, not all molecules of a gas strike the walls of their container with the same force due to variations in kinetic energy and speed resulting from their random motion and collisions.

Step by step solution

01

Understand the Kinetic Molecular Theory

The Kinetic Molecular Theory of gases makes certain assumptions about the particles in a gas. These assumptions include that gas particles are in constant, random motion, they collide with each other and the walls of the container without losing energy, and that they exert force upon collision due to their momentum. Furthermore, the distribution of the speeds (and thus kinetic energy) of the molecules follows a statistical distribution.
02

Analyze Particle Speed and Collisions

Not all gas molecules move with the same speed. Due to random motion and collisions, their speeds follow a distribution (often Maxwell-Boltzmann distribution for ideal gases), meaning there is a variety of kinetic energies at any given moment. Therefore, if the kinetic energies are different, the force exerted by the molecules during collisions with the walls will also be different.
03

Conclude Based on Forces Exerted

Because kinetic energy and speed of molecules vary, and because force exerted on the walls of the container depends on the molecule's momentum change upon collision (which in turn depends on speed and mass), it can be concluded that not all molecules of a gas strike the walls with the same force.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Maxwell-Boltzmann Distribution
Imagine a crowded dance floor where each dancer moves at a different pace, quickly reflecting the diverse energy levels among them. Similarly, gas molecules within a container exhibit a wide range of speeds, captured by the Maxwell-Boltzmann distribution. This statistical distribution is a cornerstone of the kinetic theory, describing the probability of finding a gas molecule at a particular speed at a given temperature.

At lower speeds, more molecules can be found, forming the rising slope on the graph of the distribution. As speed increases, fewer molecules travel that fast, which corresponds to the descending portion. The most probable speed is where most molecules are 'dancing'—not too fast, not too slow. This reflects the temperature's role: higher temperatures shift the peak of the curve rightward, indicating more high-energy (faster) molecules.

When applying this concept to the exercise, one understands why the forces exerted by gas molecules on container walls vary. The variability in molecular speeds, as furnished by the Maxwell-Boltzmann distribution, directly translates to variability in the momentum and therefore the force upon collision.
Kinetic Energy of Gases
Kinetic energy is the energy of motion. For gas molecules, envision tiny, invisible spheres zooming unpredictably in every direction. This motion defines their kinetic energy, adhering to the formula: \( KE = \frac{1}{2}mv^2 \), where 'm' is the mass and 'v' the speed of a molecule. In a gas, molecules bounce around, clashing into each other, akin to balls in a lottery machine.

The kinetic energy is different for each molecule based on its speed, highlighting the individuality of their 'dance'. With varying kinetic energies comes varying impact when they meet the container; a swift molecule delivers a larger 'punch' to the walls than a sluggard. The step-by-step solution from the exercise demonstrates that kinetic energy's diversity among gas molecules explains the differing forces upon collision with the container walls. Hence, just like dancers on a floor, not every molecule 'steps' with the same force.
Molecular Collisions in Gases
Continuing with our dance floor analogy, each gas molecule's 'dance' involves countless 'spins and twists'—collisions—both with fellow molecules and the container walls. These molecular collisions are perfectly elastic under the kinetic molecular theory, meaning the molecules do not lose kinetic energy when they interact; rather, they exchange it.

In this microscopic ballroom, the collisions dictate the pressure exerted on the container walls. It's a consequence of the continuous, dynamic transfer of momentum between molecules and walls. When a molecule with greater kinetic energy collides with the wall, the change in its momentum is greater, yielding a stronger force. The diversity of these energetic encounters, as itemized in the exercise's solution, confirms that not all gas molecules exert equal force upon impacting the walls.

The dance of molecules is precise but chaotic, where every 'move'—collision—adds up to the overall pressure that is felt as a macroscopic property of the gas.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) A \(125-\mathrm{mL}\) flask contains argon at \(1.30\) atm and \(77^{\circ} \mathrm{C}\). What amount of Ar is present (in moles)? (b) A \(120 .-\mathrm{mL}\) flask contains \(2.7 \mu \mathrm{g}\) of \(\mathrm{O}_{2}\) at \(17^{\circ} \mathrm{C}\). What is the pressure (in Torr)? (c) A 20.0-L flask at \(215 \mathrm{~K}\) and 20. Torr contains nitrogen. What mass of nitrogen is present (in grams)? (d) A 16.7-g sample of krypton exerts a pressure of \(1.00 \times 10^{2} \mathrm{~m}\) Torr at \(44^{\circ} \mathrm{C}\). What is the volume of the container (in liters)? (e) A \(2.6-\mu \mathrm{L}\) ampoule of xenon has a pressure of \(2.00\) Torr at \(15^{\circ} \mathrm{C}\). How many Xe atoms are present?

Suppose that \(2.00 \mathrm{~L}\) of propane gas, \(\mathrm{C}_{3} \mathrm{H}_{8}\), at \(1.00\) atm and \(298 \mathrm{~K}\) is mixed with \(5.00 \mathrm{~L}\) of oxygen gas at the same pressure and temperature and burned to form carbon dioxide gas and liquid water. Ignore the volume of water formed, and determine the final volume of the reaction mixture (including products and excess reactant) at \(1.00 \mathrm{~atm}\) and \(298 \mathrm{~K}\) if reaction goes to completion.

The four flasks below were prepared with the same volume and temperature. Flask I contains He atoms, Flask II contains \(\mathrm{Cl}_{2}\) molecules, Flask III contains Ar atoms, and Flask IV contains \(\mathrm{NH}_{3}\) molecules. Which flask has (a) the largest number of atoms; (b) the highest pressure; (c) the greatest density; (d) the highest root mean square speed; (e) the highest molar kinetic energy?

The pressure needed to make synthetic diamonds from graphite is \(8 \times 10^{4}\) atm. Express this pressure in (a) Pa; (b) kbar; (c) Torr; (d) lb \(^{\text {inch }}{ }^{-2}\).

How does the frequency of collisions of the molecules of a gas with the walls of the container change as the volume of the gas is decreased at constant temperature? Justify your answer on the basis of the kinetic model of gases.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free