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Manganate ions, \(\mathrm{MnO}_{4}^{2-}\), react at \(2.0 \mathrm{~mol} \cdot \mathrm{L}^{-1} \cdot \mathrm{min}^{-1}\) in acidic solution to form permanganate ions and manganese(IV) oxide: \(3 \mathrm{MnO}_{4}{ }^{2-}(\mathrm{aq})+4 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 2 \mathrm{MnO}_{4}{ }^{-}(\mathrm{aq})+\mathrm{MnO}_{2}(\mathrm{~s})+\) \(2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\). (a) What is the rate of formation of permanganate ions? (b) What is the rate of reaction of \(\mathrm{H}^{+}(\mathrm{aq})\) ? (c) What is the unique rate of the reaction?

Short Answer

Expert verified
The rate of formation of permanganate ions is approximately 1.33 mol L^-1 min^-1, the rate of reaction of H+ is approximately 2.67 mol L^-1 min^-1, and the unique rate of the reaction is approximately 0.67 mol L^-1 min^-1.

Step by step solution

01

Determine the Rate of Formation of Permanganate Ions

The stoichiometry of the reaction indicates that 3 moles of manganate ions form 2 moles of permanganate ions. Therefore, the rate of formation of permanganate ions is 2/3 times the rate of disappearance of manganate ions. We can calculate this using the rate of reaction of manganate ions which is given as 2.0 mol L^-1 min^-1.
02

Calculate the Rate of Reaction of H+

Using the stoichiometric ratios from the balanced chemical equation, we see that 4 moles of H+ react for every 3 moles of manganate ions that react. The rate of reaction of H+ can be found by multiplying the rate of disappearance of manganate ions by the ratio of 4/3.
03

Determine the Unique Rate of the Reaction

The unique rate of reaction is the rate of disappearance of reactants or the rate of formation of products divided by their stoichiometric coefficients. Since the stoichiometric coefficient for manganate ions is 3, the unique rate of the reaction can be found by dividing the rate of disappearance of manganate ions by 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Stoichiometry
Understanding reaction stoichiometry is essential when examining chemical reactions. It involves the quantitative relationship between reactants and products in a chemical equation. In the case of the reaction between manganate ions and hydrogen ions, the equation provided shows that 3 moles of manganate ions react with 4 moles of hydrogen ions to produce 2 moles of permanganate ions, some manganese(IV) oxide, and water.

Stoichiometry allows us to calculate the rates at which products are formed based on how reactants are consumed. By looking at the balanced chemical equation, one can determine the molar ratio of each reactant to each product. Here, for every 3 moles of manganate ions that react, 2 moles of permanganate ions are formed. This ratio helps us calculate the rate of formation of permanganate ions by applying the given rate of disappearance of manganate ions.
Unique Rate of Reaction
The unique rate of a reaction is a standardized measure of how fast the reaction occurs. It is independent of which reactant or product you are looking at and is calculated by taking the rate of change in concentration of one component and dividing it by its stoichiometric coefficient in the balanced equation.

For instance, if the rate of disappearance of manganate ions is given, to find the unique rate, we divide this rate by the stoichiometric coefficient of manganate ions, which is 3 in our reaction. This gives a single rate that characterizes the reaction, making it simpler to compare with other reactions or to express the rate of consumption or formation of different components of the reaction.
Rate of Formation
The rate of formation pertains to how quickly products are created in a chemical reaction. This can be calculated using reaction stoichiometry and the rates of disappearance of the reactants. In our example, once the rate at which manganate ions disappear is known, we can predict the rate at which permanganate ions are formed.

To calculate the rate of formation of permanganate ions from the given data, we utilize the stoichiometric ratio. This means mathematically expressing the rate as a fraction, 2/3 in this case, of the rate at which manganate ions are consumed. It is important to remember that the rates of formation and disappearance are intrinsically linked through the balanced chemical equation. So, by understanding one rate and the stoichiometry of the reaction, the other can be deduced.

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Most popular questions from this chapter

Derive an expression for the half-life of the reactant A that decays by a third-order reaction with rate constant \(k\).

The rate law of the reaction \(2 \mathrm{NO}(\mathrm{g})+2 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{N}_{2}(\mathrm{~g})+\) \(2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) is Rate \(=k[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right]\), and the mechanism that has been proposed is Step \(1 \mathrm{NO}+\mathrm{NO} \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}\) Step \(2 \mathrm{~N}_{2} \mathrm{O}_{2}+\mathrm{H}_{2} \longrightarrow \mathrm{N}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O}\) Step \(3 \mathrm{~N}_{2} \mathrm{O}+\mathrm{H}_{2} \longrightarrow \mathrm{N}_{2}+\mathrm{H}_{2} \mathrm{O}\) (a) Which step in the mechanism is likely to be rate determining? Explain your answer. (b) Sketch a reaction profile for the overall reaction, which is known to be exothermic. Label the activation energies of each step and the overall reaction enthalpy.

In the brewing of beer, ethanal, which smells like green apples, is an intermediate in the formation of ethanol. Ethanal decomposes in the following first-order reaction: \(\mathrm{CH}_{3} \mathrm{CHO}(\mathrm{g}) \longrightarrow \mathrm{CH}_{4}(\mathrm{~g})+\) \(\mathrm{CO}(\mathrm{g})\). At an elevated temperature the rate constant for the decomposition is \(1.5 \times 10^{-3} \mathrm{~s}^{-1}\). What concentration of ethanal, which had an initial concentration of \(0.120 \mathrm{~mol} \cdot \mathrm{L}^{-1}\), remains \(20.0 \mathrm{~min}\) after the start of its decomposition at this temperature?

Dinitrogen pentoxide, \(\mathrm{N}_{2} \mathrm{O}_{5}\), decomposes by first- order kinetics with a rate constant of \(0.15 \mathrm{~s}^{-1}\) at \(353 \mathrm{~K}\). (a) What is the half-life (in seconds) for the decomposition of \(\mathrm{N}_{2} \mathrm{O}_{5}\) at \(353 \mathrm{~K}\) ? (b) If \(\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]_{0}=0.0567 \mathrm{~mol} \cdot \mathrm{L}^{-1}\), what will be the concentration of \(\mathrm{N}_{2} \mathrm{O}_{5}\) after \(2.0 \mathrm{~s}\) ? (c) How much time (in minutes) will elapse before the \(\mathrm{N}_{2} \mathrm{O}_{5}\) concentration decreases from \(0.0567 \mathrm{~mol} \cdot \mathrm{L}^{-1}\) to \(0.0135 \mathrm{~mol} \cdot \mathrm{L}^{-1}\) ?

Express the units for rate constants when the concentrations are in moles per liter and time is in seconds for (a) zero-order reactions; (b) first-order reactions; (c) second-order reactions.

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