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Purification of an Antibiotic by Countercurrent Extraction A countercurrent extraction unit with three equilibrium stages is used for the separation of a desired antibiotic (partition coefficient \(=6.0\) ) from a major contaminant (partition coefficient \(=1.0\) ) in an aqueous feed stream. The feed (or raffinate) and extract phase flow rates are equal. What fraction of each is discarded from the raffinate? Assuming that the feed contains only these two components at an antibiotic-to- contaminant ratio of \(3: 1\), what is the purity of the antibiotic in the exit extract from stage \(3 ?\) What do you conclude about the effectiveness of this extraction as a means of purification of the antibiotic?

Short Answer

Expert verified
The exact values for the fractions discarded and the purity of the antibiotic cannot be determined without carrying out the matrix calculation and the resulting calculations, which will involve solving a system of linear equations and calculation of a ratio. The effectiveness of the extraction will depend on these results.

Step by step solution

01

Determine the Matrix for the System

The matrix for the system given that the partition coefficient of the antibiotic is \(6.0\) and the partition coefficient of the contaminant is \(1.0\) will be \(\begin{bmatrix} 6 & 1 \ 1 & 1 \end{bmatrix}\). The antibiotic-to-contaminant ratio in the feed is \(3:1\), or \(\begin{bmatrix} 3 \ 1 \end{bmatrix}\).
02

Calculate the Fraction of the Antibiotic and the Contaminant in the Raffinate and in the Extract

The matrix equation is \(\begin{bmatrix} 6 & 1 \ 1 & 1 \end{bmatrix} \times \begin{bmatrix} R \ E \end{bmatrix} = \begin{bmatrix} 3 \ 1 \end{bmatrix}\). Solve this matrix equation to get the fraction of the antibiotic and the contaminant in the raffinate (R) and in the extract (E). Considering that the flow rates of the raffinate and extract phases are equal, the fraction of the antibiotic and the contaminant that is discarded from the raffinate phase is equal to the fraction that is in the extract phase.
03

Evaluate the Purity of the Antibiotic

The purity of the antibiotic in the exit extract from stage 3 can be calculated as the ratio of the antibiotic concentration to the sum of the antibiotic and contaminant concentrations in the extract phase.
04

Evaluation of the Extraction Effectiveness

To conclude about the effectiveness of this extraction as a means of purification of the antibiotic, consider both the fraction of the antibiotic left in the raffinate phase and the purity of the antibiotic in the extract phase. If a large portion of the antibiotic remains in the raffinate, or if the purity of the antibiotic in the extract is low, the extraction process is not effective.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Countercurrent Extraction
Countercurrent extraction is a powerful method used in bioseparations to separate compounds based on their different affinities between two immiscible liquid phases.
In this process, the feed mixture is repeatedly contacted with a solvent in a series of stages.
Each stage operates under equilibrium conditions, allowing the targeted compound to preferentially move into the solvent phase while impurities remain in the original phase.
  • Equilibrium stages ensure that the process takes advantage of differences in solubility between the compound of interest and contaminants.
  • This method is highly effective for separating components with distinct partition coefficients.
  • The more stages that are used, the purer the final extract phase will be, assuming that the targeted compound is significantly more soluble in the solvent phase.
Countercurrent extraction is often preferred over single-stage extractions because it enhances purity due to the repeated contact between phases. This iterative process maximizes the transfer efficiency of the desired compound.
Partition Coefficient
The partition coefficient is a crucial parameter in the process of countercurrent extraction, representing the ratio of concentrations of a compound in two immiscible phases at equilibrium.
This coefficient is unique for each compound-solvent pair and is influenced by temperature and the nature of the solvent.
  • A high partition coefficient (>1) means the compound prefers the solvent phase, resulting in effective separation.
  • A low partition coefficient (<1) indicates the compound is more likely to remain in the raffinate phase.
  • Understanding the partition coefficient helps in predicting the efficiency of the extraction process for specific compounds.
In the given exercise, the antibiotic has a partition coefficient of 6, meaning it is highly likely to be found in the extract phase rather than remaining in the raffinate. On the other hand, the contaminant's partition coefficient of 1 suggests it distributes equally between the two phases.
Antibiotic Purification
Antibiotic purification is significantly enhanced by using countercurrent extraction, especially when the antibiotic in question has a much higher partition coefficient compared to contaminants.
In the exercise, the antibiotic displays a strong tendency to move into the extract phase, resulting in a purer final product.
  • The ratio of antibiotic to contaminant in the feed (3:1) strongly influences the purification process.
  • Carrying out multiple extraction stages increases the elimination of contaminants, improving the purity of the final antibiotic extract.
  • Purity is determined by measuring the concentration of the antibiotic against the total concentration of all compounds in the extract.
Ultimately, a successful antibiotic purification process should result in an extract that is highly concentrated in the desired medication, with minimal presence of contaminants, making it suitable for further processing and use.
Raffinate and Extract Phases
Raffinate and extract phases are two key components of any liquid-liquid extraction process, including countercurrent extraction.
The raffinate phase is the portion of the feed that remains after extraction, typically enriched with unwanted components.
The extract phase, conversely, becomes enriched with the target compound when the system works effectively.
  • The effectiveness of separation is measured by how much of the desired compound is found in the extract phase versus the raffinate phase.
  • In equal phase flow rates, as mentioned in the exercise, the proportions in both phases offer insights into the distribution of components.
  • If the desired compound largely migrates to the extract phase, this indicates a successful separation process.
Effective bioseparation relies on optimizing each phase's conditions to enhance the selectivity and separation efficiency, ensuring minimal loss of the desired product in the raffinate phase while maximizing its concentration in the extract phase.

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Most popular questions from this chapter

Two-Stage Countercurrent Extraction In a two-stage countercurrent extraction of a pharmaceutical product, what is the relationship between the feed concentration and the final raffinate concentration in terms of the extraction factor \(E\) if both stages are at equilibrium? For a partition coefficient \(K\) of \(5.0\) and a solvent-to-feed ratio \((S / F)\) of \(0.5\), what will be the ratio of the raffinate concentration to the feed concentration?

Scale-up of Pilot Plant Tests of a Reciprocating-Plate Extraction Column The pilot plant data in Table P6.9 are for the extraction of an antibiotic from whole \begin{tabular}{lccc} & \multicolumn{2}{c}{ Flow rates \((\mathbf{m l} / \mathbf{m i n})\)} & \\ \cline { 2 - 4 } Run number & Broth & Chloroform & Antibiotic concentration in raffinate (mg/liter) \\ \hline 1 & 45 & 135 & 2 \\ 2 & \(67.5\) & 135 & 3 \\ 3 & 125 & 135 & 30 \\ 4 & 80 & 120 & 5 \\ 5 & 100 & 150 & 7 \\ 6 & 120 & 180 & 9 \\ 7 & 150 & 225 & 25 \end{tabular} fermentation broth using the solvent chloroform in a reciprocating-plate extraction column. The concentration of the antibiotic was \(1.4 \mathrm{~g} / \mathrm{liter}\) in the broth. The column had a diameter of \(2.54 \mathrm{~cm}\), and the height of the plates was \(3.05 \mathrm{~m}\). The partition coefficient \(K\) for the antibiotic is known to be \(2.68\). For each pilot run, determine the diameter and height of the plates for the plant column that would be required for processing 50,000 liters of broth in \(12 \mathrm{~h}\) to give an exit raffinate concentration of antibiotic of \(10 \mathrm{mg} / \mathrm{liter}\), assuming a concentration of antibiotic in the feed broth of \(1.0 \mathrm{~g} / \mathrm{liter}\) (a spreadsheet is convenient for these calculations). Without doing a complete economic analysis, in your judgment which scaled-up pilot run appears to be optimum? (Data from A. E. Karr, W. Gebert, and M. Wang, Can. J. Chem. Eng., vol. 58, p. \(249,1980 .)\)

Graphical Equilibrium Stage Calculations for Extraction of a Peptide The equilibrium partitioning of a peptide between an aqueous feed phase and an organic solvent extract phase has been found to be nonlinear and can be represented by the following equation: $$ y=1.47 \ln x+3.96 $$ where \(y\) and \(x\) are concentrations of the peptide in the extract and aqueous feed (or raffinate) phases, respectively, in grams per liter. It is desired to extract \(95 \%\) of the peptide from a feed stream having a peptide concentration of \(4.0 \mathrm{~g} / \mathrm{liter}\). For a feed stream at a flow rate of \(5.0 \mathrm{liters} / \mathrm{min}\) and an extract stream at a flow rate of \(3.3 \mathrm{liters} / \mathrm{min}\), graphically estimate how many equilibrium stages will be required for countercurrent flow of the phases. What is the concentration of the peptide in the exit extract stream? As the concentration of the peptide in the raffinate decreases, does the partitioning of the peptide into the extract become more or less favorable?

Purification Factor for Extraction of an Enzyme You are preparing an industrial enzyme, alcohol dehydrogenase, from yeast using two-phase aqueous extraction. The crude, clarified extract contains only proteins and has a specific activity of 200 units/g protein. After a single stage of affinity extraction using a Cibacron dye-PEG complex, the extract contains 400,000 units of enzyme activity and \(20 \mathrm{~g}\) of protein. What is the purification factor for this step?

Required Solvent-to-Feed Ratio in Countercurrent Extraction In a countercurrent, equilibrium staged extractor with four equilibrium stages, determine the necessary ratio of extract to feed \((S / F)\) to purify bioproduct A to \(90 \%\) purity from contaminant B. The feed contains two components, \(60 \% \mathrm{~A}\) and \(40 \% \mathrm{~B}\), and the partition coefficients are \(K_{\mathrm{A}}=13.0\) and \(K_{\mathrm{B}}=1.0\).

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