Chapter 1: Problem 8
Calculations for the Purification of a Recombinant Protein The purification of a recombinant protein is carried out starting with 100 liters of a clarified cell lysate (i.e., the cells have been lysed, and the cell debris has been removed to give a clarified solution), which has a total protein concentration of \(0.36 \mathrm{mg} / \mathrm{ml}\) and a recombinant protein concentration of \(2.2 \mathrm{U} / \mathrm{ml}\), where U denotes units of biological activity of the recombinant protein. It is known that the completely pure recombinant protein has a specific activity of \(40.0 \mathrm{U} / \mathrm{mg}\). Purification is continued until a chromatography step that yields \(2.0\) liters of a fraction containing the protein, with a total protein concentration of \(1.11 \mathrm{mg} / \mathrm{ml}\) and a recombinant protein concentration of \(43.2 \mathrm{U} / \mathrm{ml}\).For the recombinant protein, calculate the starting and ending purity, the starting and ending specific activity, and the percentage yield and fold purification through the chromatography step.
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