Chapter 7: Problem 3
The growth of \(S\). cerevisiae on glucose under anaerobic conditions can be described by the following overall reaction: $$ \begin{aligned} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+\beta \mathrm{NH}_{3} \longrightarrow & 0.59 \mathrm{CH}_{1.74} \mathrm{~N}_{0.2} \mathrm{O}_{0.45} \text { (biomass) }+0.43 \mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3}+1.54 \\ & \mathrm{CO}_{2}+1.3 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+0.036 \mathrm{H}_{2} \mathrm{O} \end{aligned} $$ a. Determine the biomass yield coefficient \(Y_{X / S}\). b. Determine the product yield coefficients \(Y_{\mathrm{EtOHS}}, Y_{\mathrm{CO}_{2} / \mathrm{S}}, Y_{\mathrm{C}_{3} \mathrm{H}_{2} \mathrm{O} / \mathrm{S}}\). c. Determine the coefficient \(\beta\).
Short Answer
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Key Concepts
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