Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Certain naphthalene derivatives, such as the dansyl group, exhibit a weak yellow fluorescence when they are in a highly polar environment (such as water) and an intense blue fluorescence when they are in a markedly nonpolar environment (such as hexane). The binding of \(\varepsilon\) -dansyl-lysine to specific antibody is accompanied by a marked increase in its fluorescence intensity and a shift in color from yellow to blue. What does this finding reveal about the hapten-antibody complex?

Short Answer

Expert verified
The hapten-antibody complex creates a nonpolar environment for the dansyl group.

Step by step solution

01

Understand the Context

In this exercise, we’re analyzing the fluorescence characteristics of aphthalene derivatives in various environments. Specifically, we observe that certain derivatives change color and intensity based on their surrounding polarity.
02

Analyze Polar vs. Nonpolar Environments

The dansyl group exhibits different fluorescence colors in polar (water) vs. nonpolar (hexane) environments: yellow in polar and blue in nonpolar.
03

Evaluate the Observed Phenomenon

When \(\varepsilon\)-dansyl-lysine binds to a specific antibody, its fluorescence changes to intense blue from yellow, indicating a shift to a nonpolar environment.
04

Conclusion about the Environment

The change to blue fluorescence upon binding suggests that the hapten-antibody complex provides a nonpolar environment to the dansyl group.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar and Nonpolar Environments
The concept of polar and nonpolar environments is crucial to understanding fluorescent behavior in chemistry. Polar environments, like water, have molecules with unequal distribution of charge, resulting in dipoles. These dipoles interact strongly with charged or polar substances, influencing properties like solubility and fluorescence.

Nonpolar environments, such as hexane, do not have these internal charges. They are neutral and only contain molecules with nearly equal sharing of electrons. This difference radically alters how substances exhibit properties like fluorescence intensity and color.

The behavior of the dansyl group serves as a great example of this. In polar settings it emits weak yellow fluorescence. Conversely, in nonpolar environments, it shows intense blue fluorescence. This shift indicates how molecular surroundings influence optical properties.
Hapten-Antibody Interaction
The binding between a hapten and an antibody is specific and informative. Haptens are small molecules that, when combined with larger proteins, elicit an immune response. Antibodies are proteins designed to bind specifically to these haptens and neutralize them.

When a hapten like \(\varepsilon\)-dansyl-lysine binds to its antibody, a change occurs, as shown by \(\varepsilon\)-dansyl-lysine's shift in fluorescence. This shift from yellow to blue suggests that the hapten, upon binding, is surrounded by a less polar environment than water, resembling more of a nonpolar milieu.

This fluorescence change indicates the precise nature of the hapten-antibody interaction, providing insights into the structure of the complex. This reaction is not only crucial for understanding how antigens are neutralized but also provides tools for studying biochemical environments.
Dansyl Group Fluorescence
The dansyl group is a common fluorescent probe used in scientific studies due to its clear changes in fluorescence based on its environment. When in polar environments like water, this group only shows a weak yellow fluorescence. However, its fluorescence becomes strong and blue in nonpolar environments, such as hexane.

The change in intensity and color of the fluorescence is used as a sensitive indicator of the local environment around the dansyl group. The movement from a weak yellow to intense blue signifies a transition to a less polar, more nonpolar setting.

This makes the dansyl group a valuable tool in research, such as monitoring changes upon binding interactions in complex biological systems or mapping the polarity of various environments. The study of such fluorescence is crucial for applications in biochemical and pharmacological research, aiding in the understanding of molecular interactions and dynamics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Protein tyrosine phosphatases, such as the molecule CD45 expressed in both B cells and T cells, play important roles in activating such protein tyrosine kinases as Fyn and Lck, which are quite similar to Src. Suggest a mechanism for the activation of such protein kinases by the removal of a phosphoryl group from a phosphotyrosine residue.

The standard free energy of binding of \(\mathrm{F}_{\text {ab }}\) derived from an antiviral \(\mathrm{IgG}\) is \(-29 \mathrm{kJ} \mathrm{mol}^{-1}\) \(\left(-7 \mathrm{kcal} \mathrm{mol}^{-1}\right)\) at \(25^{\circ} \mathrm{C}\) (a) Calculate the dissociation constant of this interaction. (b) Predict the dissociation constant of the intact \(\mathrm{IgG}\), assuming that both combining sites of the antibody can interact with viral epitopes and that the free-energy cost of assuming a favorable hinge angle is \(12.6 \mathrm{kJ} \mathrm{mol}^{-1}\left(-3 \mathrm{kcal} \mathrm{mol}^{-1}\right)\)

The proteolytic digestion of a population of IgG molecules isolated from human serum results in the generation of \(\mathrm{F}_{\mathrm{ab}}\) and \(\mathrm{F}_{\mathrm{c}}\) fragments. Why do \(\mathrm{F}_{\mathrm{c}}\) fragments crystallize more easily than \(\mathrm{F}_{\text {ab }}\) fragments generated from such a population?

Cells, including immune cells, degrade mRNA molecules in which no long open reading frame is present. The process is called nonsense-mediated RNA decay. Suggest a role for this process in immune cells.

A strain of mice has been identified that does not respond to LPS. This lack of response is due to a single amino acid change in the TIR domain of mouse TLR-4. Propose an explanation for the lack of response.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free