Chapter 13: Problem 10
Concerted opening. Suppose that a channel obeys the concerted allosteric model (MWC model, p. 200). The binding of ligand to the \(R\) state (the open form) is 20 times as tight as that to the T state (the closed form). In the absence of ligand, the ratio of closed to open channels is \(10^{5}\). If the channel is a tetramer, what is the fraction of open channels when \(1,2,3,\) and 4 ligands are bound?
Short Answer
Step by step solution
Understanding the Model
Defining Parameters
Calculating the Partition Function
Calculating Probability for Each Ligand Binding
Evaluating Fractions Numerically for Bound Ligands
Interpreting the Results
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
MWC Model
- The Relaxed state (R), which has higher affinity for the ligand.
- The Tense state (T), which has lower affinity for the ligand.
Ligand Binding
- The R state binds ligands 20 times more tightly than the T state in our given scenario.
- Binding affinity is described by binding constants, denoted by \( K_R \) for the R state and \( K_T \) for the T state, where \( K_T = 20 K_R \).
R and T States
- R State: The high-affinity state which binds ligands very tightly. It is often associated with increased biological activity.
- T State: The low-affinity state which binds ligands less effectively. It is typically more stable in the absence of a ligand.
Tetramer
- Each subunit can bind a ligand, contributing to the overall protein's conformational state using cooperative binding dynamics.
- The tetramer structure implies there are four possible binding sites for ligands, significantly influencing the protein's behavior under the concerted allosteric model.