Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Component parts. Raffinose is a trisaccharide and a minor constituent in sugar beets. (a) Is raffinose a reducing sugar? Explain. (b) What are the monosaccharides that compose raffinose? (c) \(\beta\) -Galactosidase is an enzyme that will remove galactose residues from an oligosaccharide. What are the products of \(\beta\) galactosidase treatment of raffinose?

Short Answer

Expert verified
(a) No, raffinose is not a reducing sugar. (b) It is composed of galactose, glucose, and fructose. (c) The products are galactose and sucrose.

Step by step solution

01

Define reducing sugar

A reducing sugar is one that has a free aldehyde or ketone group, meaning it can donate electrons to another molecule, reducing it in the process. To determine if raffinose is a reducing sugar, we need to look for a free anomeric carbon that can open to form an aldehyde or ketone.
02

Analyze raffinose structure for reducing capability

Raffinose consists of three monosaccharides: galactose, glucose, and fructose. The glucose unit (linked through its anomeric carbon) is connected to the fructose via this anomeric carbon, preventing it from opening to form a free aldehyde or ketone. Hence, there is no free reducing end.
03

Identify the monosaccharides in raffinose

Raffinose is a trisaccharide composed of galactose, glucose, and fructose. It is specifically composed of galactose-(1→6)-glucose-(1→2)-fructose, where fructose is at the non-reducing end connected via a 1,2-glycosidic bond with glucose.
04

Function of β-Galactosidase

β-Galactosidase is an enzyme that hydrolyzes the terminal, non-reducing β-galactose residues in β-galactosides. It specifically cleaves the galactose unit bonded via β(1→6) linkage to glucose.
05

Determine products of β-Galactosidase treatment

When raffinose is treated with β-galactosidase, the galactose unit is removed from the trisaccharide. This leaves sucrose, which is composed of glucose and fructose, as the remaining product after the cleavage of galactose.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reducing Sugars
Reducing sugars are carbohydrates that can donate electrons by having a free aldehyde or ketone group. This ability is important in many chemical reactions, including those involved in food browning and cellular metabolism. To determine if a sugar is reducing, look for a free anomeric carbon that can open up to form this group. In the case of raffinose, it is a non-reducing sugar. This is because its anomeric carbon is involved in a glycosidic bond formation, linking the glucose unit to fructose, preventing it from opening and exhibiting reducing properties.
Monosaccharides
Monosaccharides are the simplest form of carbohydrates, functioning as the basic building blocks of more complex sugars like disaccharides and polysaccharides. Each monosaccharide is composed of a single sugar molecule, such as glucose, fructose, or galactose. Raffinose is a trisaccharide, composed of three monosaccharides:
  • Galactose
  • Glucose
  • Fructose
Together, they form raffinose, linked through specific glycosidic bonds. Understanding the structure of these monosaccharides helps us comprehend how they contribute to larger carbohydrate molecules.
Enzyme Activity
Enzymes play a crucial role in carbohydrate metabolism by facilitating the breakdown of sugars.
  • Beta-Galactosidase is an enzyme responsible for hydrolyzing galactose residues from oligosaccharides like raffinose.
  • It specifically targets the β(1→6) linkages between galactose and glucose in raffinose.
Through enzymatic activity, complex sugars are broken down into simpler forms, which are easier for the body to utilize. The main function of β-galactosidase regarding raffinose is to remove the galactose unit, leaving behind sucrose (glucose and fructose). This process underscores the importance of enzymes in metabolic pathways.
Glycosidic Bonds
Glycosidic bonds are crucial connections linking monosaccharide units in carbohydrates. These bonds determine the properties and digestibility of the carbohydrate molecule. In raffinose, there are two key glycosidic linkages:
  • Galactose is linked to glucose via a β(1→6) bond.
  • Glucose is linked to fructose via a (1→2) bond.
Understanding these bonds is important as they influence the nutritional and enzymatic breakdown of raffinose. These glycosidic bonds are stable but can be broken by specific enzymes like β-galactosidase, allowing for controlled metabolism and energy release.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Anomeric differences. \(\propto\) -D-Mannose is a sweet-tasting sugar. \(\beta- D-M\) annose, on the other hand, tastes bitter. A pure solution of \(\alpha-D\) -mannose loses its sweet taste with time as it is converted into the \(\beta\) anomer. Draw the \(\beta\) anomer and explain how it is formed from the \(\alpha\) anomer.

Making ends meet. (a) Compare the number of reducing ends to nonreducing ends in a molecule of glycogen. (b) As we will see in Chapter 21 , glycogen is an important fuel-storage form that is rapidly mobilized. At which end- the reducing or nonreducing - would you expect most metabolism to take place?

Mutarotation. The specific rotations of the \(\alpha\) and \(\beta\) anomers of \(\mathrm{D}\) -glucose are +112 degrees and +18.7 degrees, respectively. Specific rotation, \([\alpha]_{\mathrm{D}},\) is defined as the observed rotation of light of wavelength 589 nm (the \(D\) line of a sodium lamp) passing through \(10 \mathrm{cm}\) of a \(1 \mathrm{g} \mathrm{ml}^{-1}\) solution of a sample. When a crystalline sample of \(\alpha\) -D-glucopyranose is dissolved in water, the specific rotation decreases from 112 degrees to an equilibrium value of 52.7 degrees. On the basis of this result, what are the proportions of the \(\alpha\) and \(\beta\) anomers at equilibrium? Assume that the concentration of the open-chain form is negligible.

Mapping the molecule. Each of the hydroxyl groups of glucose can be methylated with reagents such as dimethylsulfate under basic conditions. Explain how exhaustive methylation followed by the complete digestion of a known amount of glycogen would enable you to determine the number of branch points and reducing ends.

Couples. Indicate whether each of the following pairs of sug. ars consists of anomers, epimers, or an aldose-ketose pair: (a) \(\quad D\) -glyceraldehyde and dihydroxyacetone (b) \(D\) -glucose and \(D\) -mannose (c) \(\quad D\) -glucose and \(D\) -fructose (d) \(\alpha-D\) -glucose and \(\beta-D\) -glucose (e) \(D\) -ribose and \(D\) -ribulose (f) \(\quad D\) -galactose and \(D\) -glucose

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free