Chapter 6: Problem 19
If methanal, \(\mathrm{H}_{2} \mathrm{C}=\mathrm{O}\), were protonated to give \(\mathrm{H}_{2} \mathrm{C}=\mathrm{OH}\), would you expect the \(\mathrm{C}=\mathrm{O}-\mathrm{H}\) angle to be closer to \(180^{\circ}, 120^{\circ}, 109^{\circ}\), or \(90^{\circ}\) ? Explain.
Short Answer
Expert verified
The \( \mathrm{C}=\mathrm{O}-\mathrm{H} \) angle should be close to \( 120^{\circ} \).
Step by step solution
01
Identify Protonation Effect
Protonating methanal, \( \mathrm{H}_{2} \mathrm{C}=\mathrm{O} \), leads to the formation of \( \mathrm{H}_{2} \mathrm{C}=\mathrm{OH} \). This changes the structure from a simple aldehyde to a protonated derivative, affecting the bond angles around the carbon atom.
02
Determine Hybridization
In \( \mathrm{H}_{2} \mathrm{C}=\mathrm{OH} \), the carbon atom is still involved in a double bond with oxygen. The hybridization of carbon in such a scenario usually remains \( sp^2 \), which corresponds to an ideal bond angle of \( 120^{\circ} \).
03
Consider Resonance and Bond Lengths
Protonation introduces a positive charge on the oxygen, increasing the \( \mathrm{C-OH} \) bond polarity. This may induce a slight deviation in the angle, but since resonance and bond length factors maintain \( sp^2 \) hybridization, the angle remains close to \( 120^{\circ} \).
04
Conclusion on Bond Angle
Given the \( sp^2 \) hybridization and relative resonance stability, the \( \mathrm{C}=\mathrm{O}-\mathrm{H} \) angle in \( \mathrm{H}_{2} \mathrm{C}=\mathrm{OH} \) after protonation is expected to be close to \( 120^{\circ} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bond Angles
When we talk about bond angles, we are referring to the angle formed between three atoms across at least two bonds. In a molecule like protonated methanal \( \mathrm{H}_2\mathrm{C}=\mathrm{OH} \), the main determinant of the bond angles is the hybridization of the atoms involved, here specifically the carbon atom.
- The carbon atom has an \( sp^2 \) hybridization due to its double bonds.
- This type of hybridization typically forms angles of approximately \( 120^{\circ} \).
Protonation
Protonation occurs when a proton (\( \mathrm{H}^+ \)) is added to a molecule, altering its structure and properties. In the case of methanal \( \mathrm{H}_2\mathrm{C} = \mathrm{O} \), protonation leads to the formation of a positively charged species \( \mathrm{H}_2\mathrm{C}=\mathrm{OH}^+ \). This addition impacts:
- Bond angles: The addition of a proton at the oxygen changes the electronic distribution but not the hybridization of the carbon, which primarily dictates the angle.
- Resonance structures: Protonation increases the resonance possibilities and delocalization of the positive charge across the oxygen.
Resonance
Resonance refers to the representation of a molecule through multiple structures, which depict the delocalization of electrons within the molecule. This is particularly relevant in protonated species.
- When methanal is protonated, the positive charge can be distributed between the oxygen and carbon atoms.
- This delocalization helps stabilize the molecule even with the additional positive charge.
Chemical Structure
Chemical structure defines the spatial arrangement of atoms in a molecule. It determines:
- Bond lengths and angles
- The molecule's dimensional shape
- Reactivity and intermolecular interactions