Chapter 4: Problem 3
The heat of combustion of 1 mole of liquid decane to give carbon dioxide and liquid water is \(1620.1\) kcal The heat of vaporization of decane at \(25^{\circ}\) is \(11.7\) kcal \(\mathrm{mol}^{-1}\). Calculate the heat of combustion that would be observed for all the participants in the vapor phase.
Short Answer
Expert verified
The heat of combustion for gaseous decane is 1631.8 kcal.
Step by step solution
01
Understand the Problem
We need to find the heat of combustion for decane when all participants are in the vapor phase. We know the combustion reaction for liquid decane and the heat of vaporization. Our job is to adjust the heat of combustion to account for the phase change from liquid to vapor.
02
Define Given Data
The heat of combustion for 1 mole of liquid decane is given as \(1620.1\) kcal. The heat of vaporization for decane at \(25^{\circ}\) C is \(11.7\) kcal/mol. These values will be used to calculate the combustion heat for gaseous decane.
03
Calculate Heat for Phase Change
Since we need to convert liquid decane to gaseous decane, add the heat of vaporization to the heat of combustion. This is because extra energy is required to convert the liquid decane to vapor before combustion takes place.
04
Adjust Heat of Combustion
Add the heat of vaporization to the given heat of combustion: \(1620.1\) kcal + \(11.7\) kcal = \(1631.8\) kcal. This is the heat of combustion for gaseous decane where all participants are vapor.
05
Conclusion
The calculated heat of combustion considers the phase transition from liquid to gas for decane before undergoing combustion. This adjusted value represents the energy released when decane is in vapor form during combustion.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heat of combustion
In thermochemistry, the heat of combustion refers to the energy released as heat when a substance undergoes complete combustion with oxygen. It is usually measured in units of kilocalories (kcal) or kilojoules (kJ) per mole of substance. When combusting decane, a hydrocarbon, the process involves breaking multiple carbon-hydrogen bonds to form carbon dioxide and water. This process releases a significant amount of energy.
One key point here is that the heat of combustion is typically calculated under standard conditions, which assume the products like carbon dioxide and water are in specified states – usually gaseous at certain temperatures. The given example talks about the combustion of liquid decane resulting in liquid water and gaseous carbon dioxide.
This process releases a lot of energy, and for liquid decane, it was specifically measured as 1620.1 kcal per mole. This indicates the energy obtained when decane burns fully, but it doesn't consider if decane were initially in the vapor phase, which requires additional energy adjustments.
One key point here is that the heat of combustion is typically calculated under standard conditions, which assume the products like carbon dioxide and water are in specified states – usually gaseous at certain temperatures. The given example talks about the combustion of liquid decane resulting in liquid water and gaseous carbon dioxide.
This process releases a lot of energy, and for liquid decane, it was specifically measured as 1620.1 kcal per mole. This indicates the energy obtained when decane burns fully, but it doesn't consider if decane were initially in the vapor phase, which requires additional energy adjustments.
Heat of vaporization
The heat of vaporization is the amount of energy required to transform a substance from a liquid into a gas or vapor. This transformation is a type of phase change, which is crucial in thermochemistry when considering energy calculations for reactions involving phase changes.
- For decane, the provided heat of vaporization is 11.7 kcal per mole.
- This means that it takes an additional 11.7 kcal for each mole of decane to transition from liquid to vapor before participating in a chemical reaction such as combustion.
Phase change
A phase change refers to the transition of a substance from one state of matter to another, such as solid to liquid, liquid to gas, or vice versa. In thermochemistry, phase changes are significant because they involve energy absorption or release without changing the chemical identity of a substance.
In the example with decane, the phase change involves its transition from liquid to vapor prior to combustion. This transition requires energy, termed the heat of vaporization, as discussed earlier. When calculating energies in thermochemical reactions, accounting for phase changes is necessary to accurately reflect the conditions under which a reaction takes place.
In the example with decane, the phase change involves its transition from liquid to vapor prior to combustion. This transition requires energy, termed the heat of vaporization, as discussed earlier. When calculating energies in thermochemical reactions, accounting for phase changes is necessary to accurately reflect the conditions under which a reaction takes place.
- Phase changes can either absorb energy (endothermic) or release energy (exothermic).
- In the case of decane, moving from liquid to vapor requires an endothermic input of energy.