Chapter 23: Problem 49
Compound A is chiral and is a liquid with the formula \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{O}_{2} \mathrm{~N}\). A is insoluble in water and dilute acid but dissolves in sodium hydroxide solution. Acidification of a sodium hydroxide solution of chiral A gives racemic A. Reduction of chiral A with hydrogen over nickel produces chiral compound B of formula \(\mathrm{C}_{5} \mathrm{H}_{13} \mathrm{~N}\). Treatment of chiral B with nitrous acid gives a mixture containing some chiral alcohol \(\mathrm{C}\) and some 2 -methyl-2-butanol. Write structures for compounds \(\mathrm{A}, \mathrm{B}\), and C that agree with all the given facts. Write balanced equations for all the reactions involved. Show your reasoning. In this type of problem, one should work backward from the structures of the final products, analyzing each reaction for the structural information it gives. The key questions to be inferred in the preceding problem are (a) What kind of chiral compound or compounds could give 2-methyl-2-butanol and a chiral alcohol with nitrous acid? (b) What kinds of compounds could give \(\mathrm{B}\) on reduction? (c) What does the solubility behavior of A indicate about the type of compound that it is? (d) Why does chiral A racemize when dissolved in alkali?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.