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An alternative and plausible mechanism for esterification of carboxylic acids is shown by the following steps: This mechanism corresponds to an \(S_{\mathrm{N}} 2\) displacement of water from the methyloxonium ion by the acid. How could you distinguish between this mechanism and the addition-elimination mechanism using heavy oxygen \(\left({ }^{18} \mathrm{O}\right)\) as a tracer?

Short Answer

Expert verified
Use ^{18}O in alcohol to trace the mechanism: if ^{18}O is in the ester, it's addition-elimination; if not, it's SN2.

Step by step solution

01

Understand the Mechanisms

In the SN2 displacement mechanism, there is a direct substitution of the -OH group in the carboxylic acid with the alcohol group leading to the ester formation. In the addition-elimination mechanism, the alcohol adds to the carbonyl group forming an intermediate, which then eliminates water to form the ester.
02

Introduce Heavy Oxygen

Introduce heavy oxygen ( ^{18}O ) in the alcohol or water molecule that participates in the reaction. This will help trace the path of the oxygen atom throughout the reaction.
03

Analyze Product Formation in SN2

In the SN2 mechanism, the heavy oxygen in water will be displaced, meaning it does not appear in the ester product. Thus, if ^{18}O from water appears elsewhere, it's not involved in the ester.
04

Analyze Product Formation in Addition-Elimination

In this mechanism, if the alcohol introduces heavy oxygen into the reaction, then the ^{18}O will appear in the ester formed since the oxygen originally bonds with the carbonyl in the intermediate.
05

Compare Results

Assess where the heavy oxygen ends up. If ^{18}O is found within the ester, the addition-elimination pathway is occurring. If not, the SN2 mechanism is likely.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SN2 displacement
The SN2 displacement reaction is a type of nucleophilic substitution reaction that involves a concerted mechanism. Here, "SN2" stands for "Substitution Nucleophilic Bimolecular."
This reaction type involves a nucleophile attacking an electrophile from the opposite side to the leaving group, leading to the simultaneous displacement of the leaving group. Because of this backside attack, the reaction occurs in a single step without the formation of any intermediates.
One key feature of the SN2 mechanism is its stereochemistry. It results in the inversion of configuration at the carbon center. Imagine it as an umbrella turning inside out in a strong wind. This inversion is clear evidence of the SN2 pathway.
  • Occurs in one step.
  • Results in an inversion of stereochemistry.
  • Involves a backside attack by the nucleophile.
This means that if you start with a chiral molecule, you will end up with its non-superimposable mirror image, which is interesting in stereochemistry. Remember, SN2 displacement is sensitive to steric hindrance, meaning bulky groups around the reacting site can hinder the reaction.
Addition-Elimination
The addition-elimination mechanism involves two distinct stages. Initially, the nucleophile adds to a molecule, forming an intermediate. This is the 'addition' part of the process.
During the esterification reaction, the alcohol will first add to the carbonyl carbon of the carboxylic acid to form a tetrahedral intermediate. In the second stage, known as 'elimination,' this intermediate rearranges to expel a leaving group, leading to the formation of the desired product.
This type of mechanism is typically found in esterification reactions as it involves forming the intermediate along the reaction pathway.
  • Consists of two separate steps: addition and elimination.
  • Forms a transient intermediate during the reaction.
  • Commonly occurs in esterification reactions.
Understanding this pathway is crucial, especially in determining reaction conditions and predicting where isotopic labeling, like heavy oxygen \((^{18}O)\), will appear in the final product.
Heavy Oxygen Tracing
In chemical reactions, heavy oxygen tracing involves replacing a typical oxygen atom with a heavier isotope, such as \(^{18}O\). This use of isotopic labeling is a powerful technique for understanding the precise pathway of a chemical mechanism.
By inserting \(^{18}O\) into a specific molecule or reactant, scientists can trace the fate of the oxygen atom through various steps in the reaction. Its heavier mass makes it detectable with certain analytical techniques like mass spectrometry.

Applications in Esterification Mechanisms

When distinguishing between SN2 and addition-elimination mechanisms during esterification, heavy oxygen tracing plays a critical role. In an SN2 reaction, if \(^{18}O\) is incorporated into water, it will not appear in the ester since the water is displaced. Hence, no heavy oxygen is found in the final ester product.
In contrast, for an addition-elimination mechanism, if \(^{18}O\) was initially in the alcohol, it will incorporate into the carbonyl group of the intermediate and remain in the formed ester. This difference in the location of \(^{18}O\) allows scientists to distinguish which mechanism was operative in a given reaction.
  • Involves isotopic labeling to track oxygen atoms.
  • Helps identify the exact mechanism pathway.
  • Detectable using mass spectrometry for its heavier mass.
This differentiation is vital for understanding and optimizing synthetic pathways in chemical reactions, providing clarity and accuracy amidst complex reaction processes.

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Most popular questions from this chapter

a. Explain why trimethyloxonium salts will convert alcohols to methyl ethers at neutral or acidic \(\mathrm{pH}\), whereas either methyl iodide or dimethyl sulfate requires strongly basic reaction conditions. b. What products would you expect from the reactions of trimethyloxonium fluoroborate with (1) ethanethiol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{SH}\), (2) diethylamine, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}\), and (3) hydrogen bromide.

What are the expected products on heating the following alcohols with strong sulfuric acid? Give your reasoning. a. cyclohexanol b. a mixture of methanol and 1 -methylcyclohexanol c. \(\left(\mathrm{CH}_{2}\right)_{2} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{OH}\)

Support your explanation of each of the following facts by reasoning based on mechanistic considerations: a. \(D\) -1-Phenylethanol reacts with thionyl chloride, \(\mathrm{SOCl}_{2}\), in pyridine to give \(L\) - 1 -phenylethyl chloride by way of an intermediate chlorosulfite ester, b. 2 -Buten-1-ol and \(\mathrm{SOCl}_{2}\) in ether and a one-molar equivalent of tributylamine gives 1 -chloro-2-butene. In the absence of the base, the rearrangement product, 3-chloro-1-butene, is obtained.

Explain why oxidation of secondary alcohols with \({ }^{18} \mathrm{O}\) -labeled potassium permanganate produces an \({ }^{18} \mathrm{O}\) containing ketone in acidic solution, but not in basic solution.

Ketals are not always capable of being made in practical yields by the direct reaction of alcohols with ketones because of unfavorable equilibria. Satisfactory preparations of \(\mathrm{RO}-\mathrm{C}-\mathrm{OR}\) with \(\mathrm{R}=\) methyl or ethyl are possible through the reactions of ketones with trimethoxy- or triethoxymethane. This process requires an acid catalyst: Write the mechanistic steps involved in this acid-induced methoxy exchange reaction.

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