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What are the expected products on heating the following alcohols with strong sulfuric acid? Give your reasoning. a. cyclohexanol b. a mixture of methanol and 1 -methylcyclohexanol c. \(\left(\mathrm{CH}_{2}\right)_{2} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{OH}\)

Short Answer

Expert verified
a. Cyclohexanol forms cyclohexene b. Methanol forms dimethyl ether; 1-methylcyclohexanol forms 1-methylcyclohexene c. Forms a conjugated diene \((\mathrm{CH}_{2})_{2}\mathrm{C}=\mathrm{CH}\)

Step by step solution

01

Identify the Reaction

When alcohols are heated with strong sulfuric acid, they typically undergo dehydration reactions, where a water molecule is removed to form an alkene. Let's analyze each alcohol to determine the products.
02

Analyze Cyclohexanol

Cyclohexanol, when heated with strong sulfuric acid, will undergo a dehydration reaction to form cyclohexene. The process involves the formation of a carbocation intermediate followed by the elimination of a water molecule and a proton to form the double bond in cyclohexene.
03

Examine Mixture of Methanol and 1-Methylcyclohexanol

In the mixture, methanol itself is difficult to dehydrate to form an alkene due to lack of beta hydrogens but can form dimethyl ether as a byproduct. 1-Methylcyclohexanol, however, undergoes dehydration to produce primarily 1-methylcyclohexene as a result of elimination through carbocation formation and subsequent double bond formation.
04

Consider More Complex Alcohol: \((\mathrm{CH}_{2})_{2} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{OH}\)

The compound \((\mathrm{CH}_{2})_{2}\mathrm{C}=\mathrm{CHCH}_{2}\mathrm{OH}\) has a terminal alcohol group. This will also undergo dehydration upon heating with sulfuric acid to form \((\mathrm{CH}_{2})_{2}\mathrm{C}=\mathrm{CH}\), an extended conjugated diene, as the π-bond shifts for more stability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbocation Formation
In dehydration reactions of alcohols, the formation of a carbocation is a key step. This occurs when the alcohol substrates lose a hydroxyl group, which then allows the molecule to take on a positive charge. This positively charged ion is what we call a carbocation.

Carbocation formation is crucial because it serves as an intermediate in the transformation process. It results from the protonation of the alcohol by sulfuric acid, which then leaves as a water molecule. The stability of the carbocation can vary:
  • Tertiary carbocations are the most stable due to hyperconjugation and inductive effects.
  • Secondary carbocations are reasonably stable.
  • Primary carbocations are the least stable and often undergo rearrangements to form more stable intermediates.
Understanding carbocation stability is vital as it influences the likelihood of rearrangements during dehydration reactions.
Alkene Formation
The ultimate goal of alcohol dehydration reactions is to form an alkene. Once a stable carbocation is established, a proton is eliminated from a neighboring carbon atom forming a double bond. This elimination is what leads to the formation of an alkene, which is characterized by the presence of carbon-carbon double bonds.

In alcohol dehydration, the process follows the E1 mechanism, especially for secondary and tertiary alcohols. The steps in alkene formation can include:
  • Formation of a stable carbocation intermediate.
  • Elimination of a proton leading to the formation of a double bond.
  • Consideration of potential rearrangements to form more stable alkenes.
These transitions are crucial as they influence the yield and type of alkene produced, such as cyclohexene from cyclohexanol and methylcyclohexene from 1-methylcyclohexanol.
Alcohol Dehydration
The process of alcohol dehydration is a common organic chemistry reaction used to convert alcohols into alkenes through the removal of water. It's a critical reaction that involves losing a water molecule from the alcohol substrate.

The general procedure involves heating the alcohol in the presence of an acid catalyst like sulfuric acid, which helps facilitate the dehydration. Key points to remember about alcohol dehydration are:
  • The reaction is usually acid-catalyzed, with sulfuric acid being common.
  • It involves a two-step mechanism with formation of a carbocation.
  • The reaction rate is determined by the stability of the formed carbocation.
  • Primary alcohols rarely go through direct dehydration; they often require rearrangements.
This reaction is widely used to synthesize various alkenes, which are essential building blocks in organic synthesis.
Sulfuric Acid Catalysis
Sulfuric acid is a common catalyst in dehydration reactions due to its ability to donate protons, facilitating the conversion of alcohols into alkenes. The role of sulfuric acid is indispensable in these reactions.

Sulfuric acid serves several functions in the catalysis process:
  • Provides protons that help in forming carbocation intermediates.
  • Acts as a dehydrating agent by helping eliminate water molecules from alcohols.
  • Stabilizes the carbocation by creating an acidic environment that enhances the reaction rate.
Through these functions, sulfuric acid ensures that the reaction proceeds efficiently, facilitating the conversion of various alcohols like cyclohexanol and 1-methylcyclohexanol into their corresponding alkenes. Understanding its role is crucial for mastering alcohol dehydration reactions.

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Most popular questions from this chapter

Either tert-butyl alcohol or 2-methylpropene treated with strong sulfuric acid and hydrogen peroxide \(\left(\mathrm{H}_{2} \mathrm{O}_{2}\right)\) gives a mixture of two reasonably stable liquid compounds (A and B), the ratio of which depends on whether the hydrogen peroxide or organic starting material is in excess. The molecular formula of A is \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}_{2}\), whereas \(\mathrm{B}\) is \(\mathrm{C}_{8} \mathrm{H}_{18} \mathrm{O}_{2}\). Treatment of A and B with hydrogen over a nickel catalyst results in quantitative conversion of each compound to tert-butyl alcohol. A reacts with acyl halides and anhydrides, whereas \(\mathrm{B}\) is unaffected by these reagents. Treatment of \(1 \mathrm{~mole}\) of A with excess methylmagnesium iodide in diethyl ether solution produces 1 mole of methane and 1 mole each of tert-butyl alcohol and methanol. One mole of \(\mathrm{B}\) with excess methylmangesium iodide produces 1 mole of 2 -methoxy-2-methylpropene and 1 mole of tert-butyl alcohol. When \(\mathrm{B}\) is heated with chloroethane, it causes chloroethane to polymerize. When \(\mathrm{B}\) is heated alone, it yields 2 -propanone and ethane, and if heated in the presence of oxygen, it forms methanol, 2 -propanone, methanal, and water. Determine the structure of A an \(\mathrm{dB}\) and write equations for all reactions involved, showing the mechanisms and intermediates that are important for each. Write at least one structure for A and for B that is isomeric with your preferred structures and show how these substances would behave in each of the given reactions.

Explain why oxidation of secondary alcohols with \({ }^{18} \mathrm{O}\) -labeled potassium permanganate produces an \({ }^{18} \mathrm{O}\) containing ketone in acidic solution, but not in basic solution.

Ketals are not always capable of being made in practical yields by the direct reaction of alcohols with ketones because of unfavorable equilibria. Satisfactory preparations of \(\mathrm{RO}-\mathrm{C}-\mathrm{OR}\) with \(\mathrm{R}=\) methyl or ethyl are possible through the reactions of ketones with trimethoxy- or triethoxymethane. This process requires an acid catalyst: Write the mechanistic steps involved in this acid-induced methoxy exchange reaction.

What type of infrared absorption bands due to hydroxyl groups would you expect for trans-cyclobutane-1,2-diol and butane-1,2-diol (a) in very dilute solution, (b) in moderately concentrated solution, and (c) as pure liquids? Give your reasoning.

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