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Write the steps that could plausibly take place in the reaction of a primary alcohol with phosphorus tribromide in the presence of the weak base pyridine to give an alkyl bromide.

Short Answer

Expert verified
The primary alcohol reacts with \(PBr_3\) via an SN2 mechanism to form an alkyl bromide and dibromophosphite.

Step by step solution

01

Protonation of the Alcohol

In the presence of pyridine, a weak base, the alcohol does not undergo stepwise deprotonation. Instead, the hydroxyl group of the primary alcohol remains intact at the start.
02

Formation of the Phosphorus Tribromide Intermediate

Phosphorus tribromide (\(PBr_3\)) is combined with the alcohol, allowing it to react with the hydroxyl group. The phosphorus atom in \(PBr_3\), which is electrophilic, is attacked by the lone pair on the oxygen of the alcohol, forming a phosphite ester intermediate and resulting in the loss of one bromide ion.
03

Nucleophilic Attack by Bromide Ion

The bromide ion, released during the formation of the phosphite ester, attacks the carbon atom bonded to the oxygen, which is now a good leaving group due to its attachment to phosphorus.
04

Formation of Alkyl Bromide and Dibromophosphite

As the bromide ion displaces the phosphite ester, an alkyl bromide is formed. The byproduct is a stabilized dibromophosphite compound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Primary Alcohol Reaction
Primary alcohols are organic compounds that contain a hydroxyl group \((-OH)\) attached to a primary carbon atom, which is a carbon attached to only one other carbon. The reaction of primary alcohols often starts with the activation of the alcohol's hydroxyl group, making it a better leaving group for further chemical reactions. In the reaction with phosphorus tribromide \((PBr_3)\), a primary alcohol is typically transformed into an alkyl bromide.

This transformation is crucial because it converts an easily hydroxylated molecule into a halide, which is more reactive and useful in organic synthesis. In the presence of a weak base like pyridine, the primary alcohol does not deprotonate immediately, meaning the reaction proceeds with the hydroxyl group intact, prepared for subsequent steps.
Phosphorus Tribromide Mechanism
Phosphorus tribromide \((PBr_3)\) plays a significant role in converting a primary alcohol into an alkyl bromide by participating in a mechanism involving the formation of a phosphite ester. The phosphorus atom in \(PBr_3\) is electrophilic, meaning it is electron-deficient and can accept electron density from the lone pair on the oxygen atom in the alcohol.

When the lone pair attacks the phosphorus atom, a phosphite ester intermediate is formed. This intermediate is crucial as it increases the leaving group's potential. Additionally, this process releases a bromide ion which acts as a nucleophile in the subsequent reaction step, ensuring the overall conversion from alcohol to alkyl bromide.
Nucleophilic Substitution
Nucleophilic substitution is a fundamental type of reaction where a nucleophile, an electron-rich species, replaces a leaving group on a carbon atom. In this reaction mechanism, the bromide ion released from the phosphorus tribromide serves as the nucleophile.

The phosphite ester group, which was formed in the prior step, makes the carbon atom bonded to the oxygen more susceptible to nucleophilic attack. The bromide ion then attacks this carbon, displacing the phosphite ester and attaching to the carbon to form the desired product.

This substitution is a single, concerted step where bonds are broken and formed simultaneously, making it part of the classic \(S_N2\) mechanism common in primary carbon centers due to their lesser steric hindrance. This mechanism ensures efficient conversion of alcohols into alkyl bromides.
Alkyl Bromide Formation
The formation of alkyl bromides from primary alcohols via phosphorus tribromide and nucleophilic substitution has a strategic importance in organic chemistry. Alkyl bromides are versatile intermediates used in various synthesis reactions, including forming carbon-carbon bonds through reactions such as Grignard.

After the nucleophilic substitution occurs, the end product is a stable alkyl bromide and a dibromophosphite byproduct. Alkyl bromides are considerably more reactive compared to alcohols, facilitating further functional modifications. The entire sequence provides a reliable pathway for preparing versatile and reactive molecules for complex synthetic transformations in both laboratory and industrial settings.

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Most popular questions from this chapter

Formation of tert-butyl ethanoate by direct esterification goes very poorly: Explain why the reaction fails, and indicate the products you actually expect to form on heating a mixture of ethanoic acid and tert-butyl alcohol with sulfuric acid as a catalyst.

A suitable method of preparing tert-butyl esters is to add the carboxylic acid to 2-methylpropene. Good yields can be obtained if a strong acid catalyst is used, if water is excluded, and if the temperature is kept low: Write a mechanism for the reaction that accounts for the need for a strong acid catalyst, and why anhydrous conditions and low temperatures are necessary.

Show the mechanistic steps you expect to be involved in the oxidation of benzenecarbaldehyde (benzaldehyde) to benzenecarboxylic (benzoic) acid in an alkaline solution of potassium permanganate.

Support your explanation of each of the following facts by reasoning based on mechanistic considerations: a. \(D\) -1-Phenylethanol reacts with thionyl chloride, \(\mathrm{SOCl}_{2}\), in pyridine to give \(L\) - 1 -phenylethyl chloride by way of an intermediate chlorosulfite ester, b. 2 -Buten-1-ol and \(\mathrm{SOCl}_{2}\) in ether and a one-molar equivalent of tributylamine gives 1 -chloro-2-butene. In the absence of the base, the rearrangement product, 3-chloro-1-butene, is obtained.

The diethyl ester of cis-butenedioic acid can be prepared by heating the corresponding anhydride with ethanol and concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in benzene in a mole ratio of perhaps \(1: 2.5: 0.25 .\) Write the steps that occur in this reaction and explain how the use of benzene and more than a catalytic amount of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) makes the formation of the diethyl ester thermodynamically more favorable than with just a catalytic amount of \(\mathrm{H}_{2} \mathrm{SO}_{4}\).

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