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Predict the products of each of the following Grignard reactions before and after hydrolysis. Give reasoning or analogies for each. a. \(\mathrm{CH}_{3} \mathrm{MgI}+\mathrm{HCO}_{2} \mathrm{C}_{2} \mathrm{H}_{5} \rightarrow\) b. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}(\mathrm{MgBr}) \mathrm{CH}_{3}+2,4\) -dimethyl-3-pentanone \(\rightarrow\) c. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{MgBr}+\mathrm{CS}_{2} \rightarrow\) d. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{MgBr}+\mathrm{NH}_{3} \rightarrow\)

Short Answer

Expert verified
(a) Ethanol, (b) Tertiary alcohol, (c) Ethanethiol, (d) Ethane after hydrolysis.

Step by step solution

01

Reaction of CH3MgI with ethyl formate

The Grignard reagent CH3MgI reacts with ethyl formate (HCO2C2H5). The Grignard reagent adds to the carbonyl group in the ester, breaking the C=O double bond and forming an intermediate alkoxide. Upon hydrolysis, the intermediate is converted into a secondary alcohol. The initial reaction forms an ethoxide intermediate, and hydrolysis yields ethanol. Thus, the product after hydrolysis is ethanol.
02

Reaction of CH3CH2CH(MgBr)CH3 with an unsymmetrical ketone

In this reaction, the Grignard reagent is CH3CH2CH(MgBr)CH3, and it reacts with 2,4-dimethyl-3-pentanone. The Grignard reagent attacks the carbonyl carbon of the ketone, leading to a tertiary alcohol upon hydrolysis as the carbon chain is extended. The specific alcohol formed depends on the location of the ketone in the molecule and the Grignard attacking the less hindered carbon.
03

Reaction of CH3CH2MgBr with CS2

The Grignard reagent CH3CH2MgBr reacts with carbon disulfide (CS2). The alkyl group of the Grignard reagent attacks the carbon of CS2, forming an intermediate thiolate, which upon hydrolysis, results in the formation of a thioaldehyde or thioalcohol. Typically, this is further transformed into ethanethiol (C2H5SH) after complete hydrolysis.
04

Reaction of CH3CH2MgBr with ammonia

The Grignard reagent CH3CH2MgBr does not typically react with ammonia (NH3) because ammonia does not provide an electrophilic site for the Grignard reagent to attack. Instead, the Grignard reagent would consume the acidic proton from NH3, producing ethane (C2H6) and magnesium amide. Thus, after hydrolysis, ethane is the only organic product formed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Organic Chemistry
Organic chemistry focuses on the study of carbon-containing compounds, which encompass a wide variety of molecules and reactions. One exciting aspect of organic chemistry is the ability to create larger, more complex molecules from simpler ones through reactions like Grignard reactions. These reactions are often used to form carbon-carbon bonds, a fundamental process in organic synthesis.
By understanding organic chemistry principles, students can predict the outcomes of reactions and determine the structure of organic compounds. The Grignard reaction is one such transformation that allows chemists to synthesize alcohols from carbonyl-containing compounds. Grignard reagents react with aldehydes, ketones, and esters to form alcohols after the addition of a water molecule in a process called hydrolysis. Through these reactions, one can explore the richness and diversity of organic molecules, which form the basis for biological and synthetic processes in chemistry.
Hydrolysis
Hydrolysis is a crucial chemical process where a water molecule is used to break chemical bonds in a compound. In the context of Grignard reactions, hydrolysis refers to the addition of water to a reaction intermediate, converting it into an alcohol.
During a Grignard reaction, a Grignard reagent first reacts with a carbonyl compound, such as an aldehyde or ketone, forming an alkoxide intermediate. The hydrolysis step involves the reaction of this intermediate with water to form the final alcohol product. This step is vital as it ensures the conversion of the reactive intermediate into a stable and isolable alcohol.
Without hydrolysis, the reaction would be incomplete, leaving unstable intermediates that cannot easily be separated and used. This process highlights the essential role of water in facilitating chemical transformations in organic synthesis.
Grignard Reagents
Grignard reagents are powerful tools in organic and organometallic chemistry. They are typically represented by the general formula RMgX, where R is an alkyl or aryl group and X is a halogen such as chlorine, bromine, or iodine.
These reagents are highly reactive due to the polarized carbon-magnesium bond, where carbon carries a partial negative charge. This makes them excellent nucleophiles, meaning they are attracted to positively charged or electron-deficient sites such as carbonyl carbons in aldehydes, ketones, and esters.
  • Formation: Grignard reagents are prepared by reacting magnesium metal with organic halides.
  • Reactivity: They easily add to carbonyl compounds, forming new carbon-carbon bonds.
  • Limitations: They are highly sensitive to moisture and must be handled in anhydrous conditions to prevent premature hydrolysis.
Their versatility and ability to form alcohols through subsequent reactions make them indispensable in constructing complex organic molecules.
Alcohol Formation
Alcohol formation in Grignard reactions is a multi-step process that results from the reaction of Grignard reagents with carbonyl compounds. This process is integral to creating various types of alcohols, depending on the specific carbonyl compound used.
The type of alcohol formed during these reactions is influenced by the carbonyl compound:
  • Aldehydes react with Grignard reagents to form secondary alcohols.
  • Ketones yield tertiary alcohols upon reaction with Grignard reagents.
  • Esters can form either primary, secondary, or tertiary alcohols, depending on the Grignard reagent and the ester structure.
The essence of alcohol formation in Grignard reactions lies in the hydrolysis step. Without this, the alkoxide intermediate remains, preventing the isolation of the alcohol product. The ability to control the reaction conditions and select appropriate Grignard reagents enables chemists to create specific alcohols for further chemical applications.

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Most popular questions from this chapter

Both 2,4-D and 2,4,5-T are herbicides that have been used for weed control and as defoliating agents in jungle warfare. Apart from the arguments for or against the use of chemicals for such purposes, there have been reports of serious dermatitis among the industrial workers who produce these substances. The cause finally was traced to \(2,3,7,8\) -tetrachlorodibenzo-p-dioxin (TCDD), which is produced as an impurity in the manufacture of 2,4,5-T. This substance (TCDD) is very toxic. In addition to the dermatitis in produces, it is a potent teratogen (induces birth abnormalities). The lethal does is less than \(10^{-6} \mathrm{~g}\) for guinea pigs. Its presence in 2,4,5-T can be eliminated, but the conditions by which it is formed are pertinent to our present discussion. The production of 2,4,5-T involves the substitution of one chlorine of 1,2,4,5-tetrachlorobenzene with hydroxide ion to give 12. This is followed by a second displacement reaction, this time on chloroethanoate by the sodium salt of 12 : If the temperature of the first step exceeds \(160^{\circ}\), then two molecules of 12 react in a double nucleophilic displacement to give TCDD. a. Write reasonable mechanisms for the steps by which two molecules of 12 are converted to TCDD. b. Would you expect TCDD to be formed in the preparation of 2,4-D from 1,2,4-trichlorobenzene? Explain.

Addition of Grignard reagents, \(\mathrm{RMgX}\), to diethyl carbonate, \(\mathrm{O}=\mathrm{C}\left(\mathrm{OC}_{2} \mathrm{H}_{5}\right)_{2}\), gives tertiary alcohols, \(\mathrm{R}_{3} \mathrm{COH}\), on hydrolysis. Write the steps involved in this reaction.

In the reaction of \(14-38 e\), when the aqueous acid is mixed with 2 -methyl-2-butanol, the mixture is initially homogenous, but it soon separates into two phases. Explain why two phases appear. On separation of the phases using a separatory funnel, which layer (upper or lower) would contain the organic product? If you were unsure, how could you quickly find out?

From the nature of the carbon-metal bonds in organometallic compounds, predict the products of the following reactions. Give your reasoning. a. \(\mathrm{CH}_{3} \mathrm{MgCl}+\mathrm{ICl}\) b. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Li}+\mathrm{CH}_{3} \mathrm{OH}\) c. \(\mathrm{CH}_{3} \mathrm{Li}+\mathrm{HC} \equiv \mathrm{CH}\) d. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Li}+\mathrm{CuI}\)

Would you expect 4-chloromethoxybenzene and 4-chlorotrifluoromethylbenzene to be more, or less, reactive than chlorobenzene toward methoxide ion? Explain.

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