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a. Draw the structure and configuration of the product expected of the reaction between 1-bromo-1-hexyne and diethylborane, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{BH}\). b. When the product is treated with sodium methoxide, \(\mathrm{NaOCH}_{3}\), then with propanoic acid, trans-3-octene is formed. Show the steps involved in forming this trans-alkene.

Short Answer

Expert verified
Trans-3-octene is the result of reacting vinyl bromide with sodium methoxide and propanoic acid.

Step by step solution

01

Reaction Setup

1-Bromo-1-hexyne reacts with diethylborane, \( (\mathrm{C}_2\mathrm{H}_5)_2\mathrm{BH} \), where B attaches to the terminal carbon of the alkyne, leading to hydroboration.
02

Hydroboration

Diethylborane adds across the triple bond of 1-bromo-1-hexyne in an anti-Markovnikov fashion. This step forms a vinyl borane where the boron is attached to the terminal end of the alkyne.
03

Formation of Vinyl Bromide

The reaction forms a vinyl bromide following the hydroboration step. The molecule now has a C-Br bond and a B(C2H5)2 group attached to adjacent carbons of the double bond.
04

Reaction with Sodium Methoxide

Sodium methoxide \( \mathrm{NaOCH}_3 \) will remove the diethylborane group from the vinyl bromide, replacing it with a methoxide group.
05

Reaction with Propanoic Acid

The intermediate product from the previous step then reacts with propanoic acid, leading to the removal of the methoxy group and regeneration of a more stable alkene bond.
06

Trans-3-Octene Formation

After the treatment with sodium methoxide followed by propanoic acid, the reaction stabilizes as \( \text{trans-3-octene} \), a trans-alkene due to elimination that occurs in a trans manner.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydroboration
Hydroboration is a crucial reaction in organic chemistry that facilitates the addition of boron across carbon-carbon multiple bonds, such as alkenes and alkynes. When 1-bromo-1-hexyne reacts with diethylborane, hydroboration occurs as diethylborane,
  • adds to the triple bond of the alkyne in an orderly fashion, and
  • connects with the terminal carbon, initiating the transformation.
This transformation occurs in an anti-Markovnikov manner, meaning the boron atom attaches to the less substituted carbon atom in the alkyne. This ultimately leads to the formation of a vinyl borane, where boron is now bonded to the terminal carbon atom.
Vinyl Borane
The formation of vinyl borane is a direct consequence of the hydroboration process. Upon the addition of boron,
  • a structure emerges where the carbon-to-boron bond is formed at the extremity of the former alkyne,
  • creating what is known as a vinyl borane.
The importance of vinyl boranes lies in their reactivity, as they serve as excellent intermediates in the synthesis of various organic compounds. Here, the vinyl borane possesses a characteristic C-B bond at what was the terminal position of the 1-bromo-1-hexyne.
Sodium Methoxide
In this reaction sequence, sodium methoxide \( \mathrm{NaOCH}_3 \) plays a significant role as a nucleophile.
  • First, it reacts with the vinyl borane, effectively replacing the boron group with a methoxide group.
  • Nucleophilic substitution takes place, where the vinyl bromide formed from the hydroboration step loses the diethylborane and gains a new methoxide group.
This step is essential for the further transformation of the compound leading to the eventual formation of trans-3-octene.
Trans-3-Octene
The synthesis of trans-3-octene is a two-step process following the initial hydroboration. The vinyl bromide product treated with sodium methoxide undergoes a further reaction with propanoic acid.
  • This subsequent reaction leads to the removal of the methoxy group, favoring the generation of a stable alkene form.
  • The double bond formed in this process is in a trans configuration, thus resulting in the creation of trans-3-octene.
This trans arrangement provides the molecule with stability and lower energy due to the trans configuration of substituents around the alkene bond.
Anti-Markovnikov Addition
Anti-Markovnikov addition refers to the process where the less substituted carbon atom in a double or triple bond becomes bonded to the addend.
  • This concept is exemplified in the reaction of 1-bromo-1-hexyne with diethylborane.
  • Unlike Markovnikov's addition, where the more substituted carbon would form the bond, anti-Markovnikov addition places the new group on the less hindered carbon.
This principle allows the reaction to produce compounds like vinyl borane, steering the formation of certain products that are not accessible through traditional Markovnikov methodologies.

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Most popular questions from this chapter

What products would you expect from hydroboration of the following alkenes with a dialkylborane, \(\mathrm{R}_{2} \mathrm{BH}\), followed by isomerization at \(160^{\circ} ?\) a. \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3}\)

Balance each of the following equations. You may need to add \(\mathrm{H}_{2} \mathrm{O}\) to one side or the other of the equations. a. \(\stackrel{\oplus}{\mathrm{K}}^{\ominus} \mathrm{M} \mathrm{O}_{4}+\mathrm{RCH}=\mathrm{CH}_{2} \rightarrow \mathrm{RCO}_{2} \stackrel{\oplus}{\mathrm{K}}+\mathrm{CH}_{2}=\mathrm{O}+\mathrm{MnO}_{2}\) b. \(\mathrm{CrO}_{3}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{3} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H}+\mathrm{Cr}^{3 \oplus}\)

A hydrocarbon of formula \(\mathrm{C}_{11} \mathrm{H}_{18}\) on reaction with ozone in dichloromethane gave, after the addition of water and finely divided zinc, three products in equimolar amounts that were identified as 2 -butanone \(\left(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}\right)\), methanal \(\left(\mathrm{CH}_{2} \mathrm{O}\right)\), and cyclohexane-1,4-dione \(\mathrm{Draw}\) the structure of the hydrocarbon \(\mathrm{C}_{11} \mathrm{H}_{18} .\)

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