Chapter 13: Problem 3
In the presence of acid, iodide is oxidized by hydrogen peroxide $$ 2 \mathrm{I}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{H}_{3} \mathrm{O}^{+}(a q) \longrightarrow 4 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{I}_{2}(a q) $$ When \(\mathrm{I}^{-}\) and \(\mathrm{H}_{3} \mathrm{O}^{+}\) are present in excess, we can use the reaction's kinetics of the reaction, which is pseudo- first order in \(\mathrm{H}_{2} \mathrm{O}_{2},\) to determine the concentration of \(\mathrm{H}_{2} \mathrm{O}_{2}\) by following the production of \(\mathrm{I}_{2}\) with time. In one analysis the solution's absorbance at \(348 \mathrm{nm}\) was measured after \(240 \mathrm{~s}\). Analysis of a set of standard gives the results shown below. $$ \begin{array}{cc} {\left[\mathrm{H}_{2} \mathrm{O}_{2}\right](\mu \mathrm{M})} & \text { absorbance } \\ \hline 100.0 & 0.236 \\ 200.0 & 0.471 \\ 400.0 & 0.933 \\ 800.0 & 1.872 \end{array} $$ What is the concentration of \(\mathrm{H}_{2} \mathrm{O}_{2}\) in a sample if its absorbance is 0.669 after \(240 \mathrm{~s} ?\)
Short Answer
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