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To study the effect of an enzyme inhibitor \(V_{\max }\) and \(K_{m}\) are measured for several concentrations of inhibitor. As the concentration of the inhibitor increases \(V_{\max }\) remains essentially constant, but the value of \(K_{m}\) increases. Which mechanism for enzyme inhibition is in effect?

Short Answer

Expert verified
Competitive inhibition.

Step by step solution

01

Analyzing Enzyme Kinetics

In enzymatic reactions, parameters like \(V_{\max}\) and \(K_m\) provide vital insights. \(V_{\max}\) indicates the maximum rate of an enzyme-catalyzed reaction at saturating substrate concentration. \(K_m\), the Michaelis constant, represents the substrate concentration at which the reaction rate is half of \(V_{\max}\).
02

Reviewing Inhibition Mechanisms

Understand the basic types of enzyme inhibition: competitive, non-competitive, and uncompetitive inhibition. Competitive inhibition typically affects \(K_m\) but not \(V_{\max}\), non-competitive inhibition affects \(V_{\max}\) but not \(K_m\), and uncompetitive inhibition affects both \(K_m\) and \(V_{\max}\).
03

Identifying Effects of Inhibitor Concentration

According to the problem, the inhibitor causes \(K_m\) to increase while leaving \(V_{\max}\) unchanged. This suggests that as the inhibitor binds, the enzyme requires a higher substrate concentration to reach half of \(V_{\max}\), a hallmark of competitive inhibition.
04

Concluding the Inhibition Type

Based on the increase in \(K_m\) with constant \(V_{\max}\) across increasing inhibitor concentrations, this inhibition model aligns with competitive inhibition, where substrate and inhibitor compete for the same active site on the enzyme.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enzyme Kinetics
Enzyme kinetics is a fundamental aspect of biochemistry that deals with understanding how enzymes interact with substrates to catalyze chemical reactions. Enzymes are biological catalysts that increase the rate of reactions without being consumed in the process. The study of enzyme kinetics provides insights into the speed and efficiency of enzymatic reactions.

Two critical parameters in enzyme kinetics are the maximum reaction rate (\(V_{\text{max}}\)) and the Michaelis constant (\(K_m\)). These two values help us understand how an enzyme functions under various conditions.

Overall, the study of enzyme kinetics is crucial for understanding how metabolic pathways are regulated within cells and how these processes can be modulated by different factors like inhibitors.
Michaelis-Menten Equation
The Michaelis-Menten equation is a mathematical representation of how enzyme-catalyzed reactions proceed with respect to substrate concentration. It forms the basis for understanding enzyme kinetics and provides a way to quantify enzyme activity.

This equation is represented as: \[ v = \frac{{V_{\text{max}} [S]}}{{K_m + [S]}} \] where:
  • \(v\): the reaction rate
  • \(V_{\text{max}}\): the maximum reaction rate
  • \([S]\): substrate concentration
  • \(K_m\): the Michaelis constant
This equation tells us how changes in substrate concentration affect the reaction rate. When substrate concentration is equal to \(K_m\), the reaction rate is half of \(V_{\text{max}}\). Understanding this relationship is crucial for determining how efficiently an enzyme can work under different conditions.
Competitive Inhibition
Competitive inhibition is a type of enzyme inhibition where an inhibitor competes directly with the substrate for binding to the active site of an enzyme. This results in an increased \(K_m\) without affecting \(V_{\text{max}}\).

In the presence of a competitive inhibitor, more substrate is required to reach half-maximal reaction velocity (\(V_{\text{max}}/2\)) compared to when the inhibitor is absent. This happens because both substrate and inhibitor vie for the same binding site on the enzyme.

Conditions of competitive inhibition are a key consideration in drug design, as many drugs function by blocking the active site of target enzymes. Enhancing or inhibiting enzyme activity can be used to control metabolic pathways.
Maximum Reaction Rate
The maximum reaction rate, represented as \(V_{\text{max}}\), is the highest speed at which an enzyme-catalyzed reaction can occur when the enzyme is saturated with substrate. It reflects the enzyme's maximum catalytic activity.

When substrate concentrations are sufficient to saturate all available enzyme molecules, the reaction velocity asymptotically approaches \(V_{\text{max}}\). This value is crucial as it represents the potential efficiency of an enzyme under optimal conditions.

In biomedical research, understanding \(V_{\text{max}}\) can help us determine how to enhance or inhibit enzyme activity to achieve desired therapeutic effects. For example, changes in \(V_{\text{max}}\) resulting from enzyme mutations can lead to various disorders.
Substrate Concentration
Substrate concentration is a key factor in enzyme-catalyzed reactions. It is the amount of substrate available for conversion into products by the enzyme. The relationship between substrate concentration and reaction rate is critical in enzyme kinetics.

Lower substrate concentrations mean fewer enzyme-substrate complexes are formed, which usually results in a slower reaction rate. As substrate concentration increases, more enzyme molecules become engaged, speeding up the reaction until the maximum rate (\(V_{\text{max}}\)) is reached.

For enzymes following Michaelis-Menten kinetics, the substrate concentration relative to \(K_m\) dramatically influences how efficiently enzymes transform substrates into products. Therefore, understanding how substrate concentration affects reaction rates is essential for investigating enzyme function in metabolic pathways.

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Most popular questions from this chapter

The vitamin \(\mathrm{B}_{12}\) content of a multivitamin tablet is determined by the following procedure. A sample of 10 tablets is dissolved in water and diluted to volume in a 100 -mL volumetric flask. A 50.00 -mL portion is removed and \(0.500 \mathrm{mg}\) of radioactive vitamin \(\mathrm{B}_{12}\) having an activity of 572 cpm is added as a tracer. The sample and tracer are homogenized and the vitamin \(\mathrm{B}_{12}\) isolated and purified, producing \(18.6 \mathrm{mg}\) with an activity of 361 cpm. Calculate the milligrams of vitamin \(\mathrm{B}_{12}\) in a multivitamin tablet.

The enzyme acetylcholinesterase catalyzes the decomposition of acetylcholine to choline and acetic acid. Under a given set of conditions the enzyme has a \(K_{m}\) of \(9 \times 10^{-5} \mathrm{M}\) and a \(k_{2}\) of \(1.4 \times 10^{4} \mathrm{~s}^{-1}\). What is the concentration of acetylcholine in a sample if the reaction's rate is \(12.33 \mu \mathrm{M} \mathrm{s}^{-1}\) in the presence of \(6.61 \times 10^{-7} \mathrm{M}\) enzyme? You may assume the concentration of acetylcholine is significantly smaller than \(K_{m}\).

The concentration of chloride in seawater is determined by a flow injection analysis. The analysis of a set of calibration standards gives the following results. $$ \begin{array}{cccc} {\left[\mathrm{Cl}^{-}\right](\mathrm{ppm})} & \text { absorbance } & {\left[\mathrm{Cl}^{-}\right](\mathrm{ppm})} & \text { absorbance } \\ \hline 5.00 & 0.057 & 40.00 & 0.478 \\ 10.00 & 0.099 & 50.00 & 0.594 \\ 20.00 & 0.230 & 75.00 & 0.840 \\ 30.00 & 0.354 & & \end{array} $$ A 1.00-mL sample of seawater is placed in a 500 -mL volumetric flask and diluted to volume with distilled water. When injected into the flow injection analyzer an absorbance of 0.317 is measured. What is the concentration of \(\mathrm{Cl}^{-}\) in the sample?

Holman, Christian, and Ruzicka described an FIA method to determine the concentration of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in nonaqueous solvents. \({ }^{28}\) Agarose beads \((22-45 \mu \mathrm{m}\) diameter \()\) with a bonded acid- base indicator are soaked in \(\mathrm{NaOH}\) and immobilized in the detector's flow cell. Samples of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in \(n\) -butanol are injected into the carrier stream. As a sample passes through the flow cell, an acid-base reaction takes place between \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and \(\mathrm{NaOH}\). The endpoint of the neutralization reaction is signaled by a change in the bound indicator's color and is detected spectrophotometrically. The elution volume needed to reach the titration's endpoint is inversely proportional to the concentration of \(\mathrm{H}_{2} \mathrm{SO}_{4} ;\) thus, a plot of endpoint volume versus \(\left[\mathrm{H}_{2} \mathrm{SO}_{4}\right]^{-1}\) is linear. The following data is typical of that obtained using a set of external standards. $$ \begin{array}{cc} {\left[\mathrm{H}_{2} \mathrm{SO}_{4}\right](\mathrm{mM})} & \text { end point volume }(\mathrm{mL}) \\ \hline 0.358 & 0.266 \\ 0.436 & 0.227 \\ 0.560 & 0.176 \\ 0.752 & 0.136 \\ 1.38 & 0.075 \\ 2.98 & 0.037 \\ 5.62 & 0.017 \end{array} $$ What is the concentration of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in a sample if its endpoint volume is \(0.157 \mathrm{~mL}\) ?

Deming and Pardue studied the kinetics for the hydrolysis of \(p\) -nitrophenyl phosphate by the enzyme alkaline phosphatase. \({ }^{23}\) The reaction's progress was monitored by measuring the absorbance of \(p\) -nitrophenol, which is one of the reaction's products. A plot of the reaction's rate (with units of \(\mu \mathrm{mol} \mathrm{mL}^{-1} \mathrm{sec}^{-1}\) ) versus the volume, \(V\), in milliliters of a serum calibration standard that contained the enzyme, yielded a straight line with the following equation. $$ \text { rate }=2.7 \times 10^{-7} \mu \mathrm{mol} \mathrm{mL}^{-1} \mathrm{~s}^{-1}+\left(3.485 \times 10^{-5} \mu \mathrm{mol} \mathrm{mL}^{-2} \mathrm{~s}^{-1}\right) V $$ A 10.00 -mL sample of serum is analyzed, yielding a rate of \(6.84 \times 10^{-5}\) \(\mu \mathrm{mol} \mathrm{mL}^{-1} \mathrm{sec}^{-1}\). How much more dilute is the enzyme in the serum sample than in the serum calibration standard?

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