Question

An $80$-proof brandy is a localid="1654601482390" $40.\%(v/v)$ethanol solution. The "proof" is twice the percent concentration of alcohol in the beverage. How many milliliters of alcohol are present in localid="1654601509722" $750mL$of brandy? $(9.4)$

Short answer

As an outcome, $750mL$of whiskey comprises localid="1654601518666" $300.mL$of ethyl alcohol.

Step-by-step solution

Introduction.

An acetic solution is a solvent primarily up of water and ethanol. Sweetener ingredients can ferment into drunken energy mixtures.

Given data.

Using the volume percent phrase.

$Volumepercent(\%v/v)=\frac{volumeofsolute}{volumeofsolution}\times 100\%......\left(1\right)$

Explanation.

We offer cognac with an ethyl alcohol by volume of $40.0\%(v/v)$. Now we need to figure out just how much alcohol is in $750mL$of whiskey.

In $100ml$of brandy, $40.0mL$of ethyl alcohol represents $40.0\%(v/v)$. As a result, measure the number of alcohol in $750mL$of champagne.

$\frac{40.0mLofethylalcohol}{100\cancel{mLofbrandly}}\times 750\cancel{mLofbrandly}=300.mLofethylalcohol$

As a result, $750mL$of brandy includes $300.mL$of ethyl alcohol.