Question

How many milliliters of a $12\%(v/v)$ propyl alcohol solution would you need to obtain $4.5mL$of propyl alcohol?$(9.4)$

Short answer

As an outcome, $38mL$ of $12(v/v)$ liquid is forced to hold $4.5mL$ of solute.

Step-by-step solution

Given information

The volume of solute absorbed in a 100 mL af mixture is the volume percent v/v. The formula for calculating volume percent is:

$volumepercent(v/v)=\frac{volumesolute}{volumeofsolution}\times 100$

$12\%(v/v)$propyl alcohal indicates $12mL$propyl alcohal in a solution of $100mL$.

The volume percent converts to a conversion factor of$\frac{12mLpropylalcohol}{100mLsolution}$.

Explanation.

Find the volume of a $12\%(v/v)$solution having $4.5mL$of propyl alcohol.

The volume of the solution is,

role="math" $=\cancel{4.5\mathrm{mL}\text{propylatcohol}}\times \frac{100\mathrm{mL}\text{solution}}{\cancel{12\mathrm{mLpropytatcohol}}}$

$=38mLsolution.$

As a result, $38mL$ of $12(v/v)$ solution is required to hold $4.5mL$ of solute.