Question

If $NaCl$has a solubility of $36.0gin100g$of $H_{2}Oat100°C$. how many grams of water are needed to prepare a saturated solution containing $80.0g$of $NaCl$? $(9.3)$

Short answer

As the concluded, make a saturated solution with$80.0gNaClat20°C,222g$water is needed.

Step-by-step solution

Introduction.

A solvent is one in which there is far too much solute that adding more would cause it to dissolve.

Given data.

$36.0g$of solid $NaCl$is decomposed in $100g$of water to make a supersaturation of $NaClat20°C$.

In $(100/36)g$of water, $1g$of solid $NaCl$is digested.

Explanation.

Estimate how much water is required to make $80.0gofNaCl.$

$=\frac{100g}{36g}\times 80g$

$=222g$

To make a saturated solution holding $80.0gNaCl$at $20°C,222g$water is required.