Question

Select the container that represents the dilution of a $4\%(m/v)KCl$solution to give each of the following: $(9.5)$

a. a $2\%(m/v)KCl$solution

b. a $1\%(m/v)KCl$solution

Short answer

(part a) As a conclusion, container $2$shows a dilution of a$4\%(m/v)KCl$solution to a $2\%(m/v)KCl$solution.

(part b) As an outcome, container $3$represents a dilution of a $4\%(m/v)KCl$solution to a $1\%(m/v)KCl$solution.

Step-by-step solution

Introduction (part a)

Dilution is the process of lowering the amount of solute in a solution by adding extra more solvent to the solution, such as water.

Given data (Part a).

(part a) The solute has a dark hue, whereas the colour of the solution illuminates during dilution. We already know that the amount of solute in a pure solvent is the same as in a diluted solution. As a result, we have the following dilution expression:

$C_1{V}_1=C_2{V}_2$

The $4\%KCl$liquid has a dark blue colour. A $2\%(m/v)KCl$liquid has a content of half that of a$4\%(m/v)KCl$solution.

Explanation (Part a).

(part a) As a result, the ultimate volume of a $2\%(m/v)KCl$solution ought to be roughly twice as high a $4\%(m/v)KCl$solution.

The concentration of the solution in container $2$is nearly twice that of the $4\%KCl$solution.

As a result, container $2$illustrates the dilution of a $4\%(m/v)KCl$solution to a $2\%(m/v)KCl$solution.

Given data (Part b). 

(part b) The $4\%KCl$fluid has a dark blue colour. A $2\%(m/v)KCl$solution has a content of half that of a $4\%(m/v)KCl$solution.

Explanation (Part b).

(part b) As a result, the ultimate volume of a $1\%(m/v)KCl$solution should just be roughly double what it was a $4\%(m/v)KCl$solution.

The solution in container $3$has a volume four times that of the $4\%KCl$solution.

As a result, container $3$depicts a $4\%(m/v)KCl$solution diluted to $1\%(m/v)KCl$solution.